Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
10 | 2 |
Solving these two equations, we get : x = | 1 | and y = | 1 | . |
100 | 200 |
(15 men + 20 boy)'s 1 day's work = | ![]() |
15 | + | 20 | ![]() |
= | 1 | . |
100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 10 of 21.
Pravas said:
9 years ago
We can do also,
(6m + 8b) * 10 = (26m + 48B) * 2,
=> 60m + 80b = 52m + 96b,
=> 8m = 16b,
=> m/b = 16/8 = 2 : 1.
Total work = (6m + 8b) * 10.
= (6 * 2 + 8 * 1) * 10 = 200.
As per question, 15 men and 20 boys will do the same work in => (15 * 2 + 20 * 1) = 50 i.e That is m/b = 2 : 1.
Total days = total work/total men and boys => 200/50 = 4 days.
(6m + 8b) * 10 = (26m + 48B) * 2,
=> 60m + 80b = 52m + 96b,
=> 8m = 16b,
=> m/b = 16/8 = 2 : 1.
Total work = (6m + 8b) * 10.
= (6 * 2 + 8 * 1) * 10 = 200.
As per question, 15 men and 20 boys will do the same work in => (15 * 2 + 20 * 1) = 50 i.e That is m/b = 2 : 1.
Total days = total work/total men and boys => 200/50 = 4 days.
(2)
Anton said:
9 years ago
How to get 15/100 + 20/200 = 4?
Mageswari.G said:
9 years ago
@Meera,
How y = 1/200? Please explain me.
How y = 1/200? Please explain me.
RISHU said:
9 years ago
8 + 6 = 14,
So totally 14 men and boys. They work for 10 days.
Then, total work of 14 men and boys in 10 days = 14 * 10 = 140.
Now 15 + 20 * x = 140,
And x = 140/35 = 4.
So totally 14 men and boys. They work for 10 days.
Then, total work of 14 men and boys in 10 days = 14 * 10 = 140.
Now 15 + 20 * x = 140,
And x = 140/35 = 4.
Rathod said:
9 years ago
Easiest way:
6 men and 8 boys = 1/10 days.
5 men and 48 boys = ?
6 * 5/2 and 48 * 5/2 = 1/10 * 5/2,
15 men and 48 boys = 4 days.
6 men and 8 boys = 1/10 days.
5 men and 48 boys = ?
6 * 5/2 and 48 * 5/2 = 1/10 * 5/2,
15 men and 48 boys = 4 days.
Gopi said:
9 years ago
Thank you so much @Meera, your method is such wonderful for pure solving.
DINESH G said:
9 years ago
06m + 08b = 1/10-------->eq 1.
26m + 48b = 1/2---------->eq 2.
15m + 20b = ?------------->eq 3.
Sol:.
From eq 1 & 2.
60m + 80b = 1.
52m + 96b = 1.
It is equals to 1. So,
60m + 80b = 52m + 96b,
8m = 16b,
M = 2b.
Now substitute in eq 3,
30b + 20b = x.
50b = x---------->eq 4.
Now in eq 1,
12b + 8b = 1/10.
20b = 1/10------->eq 5.
Now compare both eq 4 & 5,
50 * x = 20 * 10.
X = 4 days.
26m + 48b = 1/2---------->eq 2.
15m + 20b = ?------------->eq 3.
Sol:.
From eq 1 & 2.
60m + 80b = 1.
52m + 96b = 1.
It is equals to 1. So,
60m + 80b = 52m + 96b,
8m = 16b,
M = 2b.
Now substitute in eq 3,
30b + 20b = x.
50b = x---------->eq 4.
Now in eq 1,
12b + 8b = 1/10.
20b = 1/10------->eq 5.
Now compare both eq 4 & 5,
50 * x = 20 * 10.
X = 4 days.
SS Gour said:
9 years ago
6m + 8b = 10
3m + 4b = 20
Hence,
15m + 25 = 20/5 (4 days, ans)
3m + 4b = 20
Hence,
15m + 25 = 20/5 (4 days, ans)
Muruganantha iyappan said:
9 years ago
In the given answer, how to solve 6x+8y=1/10 AND 26x+48y=1/2?
Rahul said:
9 years ago
How to solve 8y = 4/100, please help me.
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