Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 7 of 21.
Bavi said:
1 decade ago
Strength*time/work = 1.
14*10/w = 74*2/w = 35*x/w.
'w' in the denominator will get cancel.
So 140 = 148 = 35x.
So equate one divisible no.
140 = 35x.
x = 4.
4 days will be the answer.
14*10/w = 74*2/w = 35*x/w.
'w' in the denominator will get cancel.
So 140 = 148 = 35x.
So equate one divisible no.
140 = 35x.
x = 4.
4 days will be the answer.
Kriti said:
5 years ago
6men, 8boys take 10 days.
(6men, 8boys)*5 i.e. 30men ad 40boys take 2 days to complete the work.
Let 15men, 20boys take x days.
(15men, 20boys) * 2 take (x/2)days.
hence 2 = (x/2),
x = 4.
(6men, 8boys)*5 i.e. 30men ad 40boys take 2 days to complete the work.
Let 15men, 20boys take x days.
(15men, 20boys) * 2 take (x/2)days.
hence 2 = (x/2),
x = 4.
(3)
RISHU said:
9 years ago
8 + 6 = 14,
So totally 14 men and boys. They work for 10 days.
Then, total work of 14 men and boys in 10 days = 14 * 10 = 140.
Now 15 + 20 * x = 140,
And x = 140/35 = 4.
So totally 14 men and boys. They work for 10 days.
Then, total work of 14 men and boys in 10 days = 14 * 10 = 140.
Now 15 + 20 * x = 140,
And x = 140/35 = 4.
Vineeth TC said:
6 years ago
To apply in equation we need to convert days in to work they did. Let's assume they make 20 chairs (LCM).
6m + 8b =2 -->(1) (total 20 chairs;per day 2 chairs).
26m+48b=10 -->(2).
6m + 8b =2 -->(1) (total 20 chairs;per day 2 chairs).
26m+48b=10 -->(2).
Nav Raj Bhatta said:
4 years ago
Find the relation between first, second to third equation.
6M+8B=10
26M+48B=2
15M+20B=?.
Now taking first equation;
6M + 8B = 10.
60M + 80B = 1.
30M + 40B = 2.
15M + 20B = 4.
6M+8B=10
26M+48B=2
15M+20B=?.
Now taking first equation;
6M + 8B = 10.
60M + 80B = 1.
30M + 40B = 2.
15M + 20B = 4.
(68)
Ravikiran said:
6 years ago
If 6 men and 8 boys take 10days to complete a work.
Which means 3 men and 4 boys take 20days to complete a work.
Then 3*5 (15 men) and 4*5(20 boys) take (20/5) which is 4 days.
Which means 3 men and 4 boys take 20days to complete a work.
Then 3*5 (15 men) and 4*5(20 boys) take (20/5) which is 4 days.
(2)
Bhanu Chander said:
1 decade ago
(6Men+8Boy).10=(26Men+48Boy).2
solve the above eq
1Men=2Boy
15Men+20Boy=25Men
6men+ 4men=(// 1men=2Boy)
10men ---10days
25men---?
10*10=25*D
D=4days
25men=15men+20boy=4days
solve the above eq
1Men=2Boy
15Men+20Boy=25Men
6men+ 4men=(// 1men=2Boy)
10men ---10days
25men---?
10*10=25*D
D=4days
25men=15men+20boy=4days
Manoj said:
1 decade ago
Hey guys. Please solve this question.
15 men + 18 women completes a work in 10 days.
If 1 man's 1 day work = 1 woman's 3/4 work of 1 day.
Then,
9 men + 14 woman = ? days.
15 men + 18 women completes a work in 10 days.
If 1 man's 1 day work = 1 woman's 3/4 work of 1 day.
Then,
9 men + 14 woman = ? days.
Sushil Mishra said:
1 decade ago
Thanks Sidharth, but will you tell me that this types of combination will be the make in every equation mean can we get as simplest way or common part in the each question.
Arjun said:
9 years ago
This is also easy way friends.
6x + 8y = 1/10,
2(3x+4y) = 1/10,
3x+4y = 1/20,
Both side multiple with 5.
15x + 20y = 1/4,
So 1/4 work complete =1 day,
Total work = 4days.
6x + 8y = 1/10,
2(3x+4y) = 1/10,
3x+4y = 1/20,
Both side multiple with 5.
15x + 20y = 1/4,
So 1/4 work complete =1 day,
Total work = 4days.
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