Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
201 comments Page 7 of 21.
Atul1487 said:
1 decade ago
We can do this in single step.
6 men and 8 boys can do work in 10 days.
So 6m+8b=1/10.
So we have to find 15m+20b=?
6m+8b=1/10.
Divide each term by 2 in both side we get,
3m+4b=1/20.
And multiply each term with 5.
15m+20b=5*120.
15m+20b=1/4.
So answer is 4 days simple.
6 men and 8 boys can do work in 10 days.
So 6m+8b=1/10.
So we have to find 15m+20b=?
6m+8b=1/10.
Divide each term by 2 in both side we get,
3m+4b=1/20.
And multiply each term with 5.
15m+20b=5*120.
15m+20b=1/4.
So answer is 4 days simple.
Jabi Mir said:
1 decade ago
We have two equations; 6x + 8y = 1/10 & 26x + 48y = 1/2.
We can write them as' 60x + 80y = 1 ...(1) & 52x + 96y = 1 ...(2).
Since work is same, equation 1 = equation 2.
i.e, 60x+ 80y = 52x+ 96y => 60x-52x = 96y-80y => 8x = 16Y.
or x/y = 16/8 => x=2y, Now substitution value of x in = n(1).
60 x 2y + 80y =1 => 120y +80y = 1.
or, 200y = 1 or y = 1/200.
Similarly, Now we can calculate value of x by substituting value of Y in any equation above.
We can write them as' 60x + 80y = 1 ...(1) & 52x + 96y = 1 ...(2).
Since work is same, equation 1 = equation 2.
i.e, 60x+ 80y = 52x+ 96y => 60x-52x = 96y-80y => 8x = 16Y.
or x/y = 16/8 => x=2y, Now substitution value of x in = n(1).
60 x 2y + 80y =1 => 120y +80y = 1.
or, 200y = 1 or y = 1/200.
Similarly, Now we can calculate value of x by substituting value of Y in any equation above.
Deepak Patgar said:
1 decade ago
6 men and 8 boys.
15 men and 20 boys.
If we look at the data carefully they are in the ratio 1:2.5.
i.e. 6:15 and 8:20 are same as 1:2.5.
So the number of days required for 15 men and 20 boys will be 10/2.5=4 days.
(Note: this method can be applied only when the ratios are same).
15 men and 20 boys.
If we look at the data carefully they are in the ratio 1:2.5.
i.e. 6:15 and 8:20 are same as 1:2.5.
So the number of days required for 15 men and 20 boys will be 10/2.5=4 days.
(Note: this method can be applied only when the ratios are same).
Shgfgh said:
1 decade ago
2x+3y = 1/10 ----- (1).
3x+2y = 1/8 ------ (2).
We want to find: 2x+1y = ?---- (3).
Any one can solve this.
3x+2y = 1/8 ------ (2).
We want to find: 2x+1y = ?---- (3).
Any one can solve this.
Manoj said:
1 decade ago
Hey guys. Please solve this question.
15 men + 18 women completes a work in 10 days.
If 1 man's 1 day work = 1 woman's 3/4 work of 1 day.
Then,
9 men + 14 woman = ? days.
15 men + 18 women completes a work in 10 days.
If 1 man's 1 day work = 1 woman's 3/4 work of 1 day.
Then,
9 men + 14 woman = ? days.
Tamilazhagan said:
1 decade ago
Why we consider 10 day as 1/10 and 2 day as 2/10?
Krishna said:
1 decade ago
(6M & 8B)10Days > (60M & 80B)..(1).
(26M & 48B)2Days > (52M & 96B)...(2).
Subtract 1 And 2 We get 8M & 16B.
Time Taken To Complete the work = Ratio= 2(M):1(B).
Now, (15M & 20B) = ? ...(03).
Put the ratio of 2:1 in (03),
We get 50.
Also put ratio in (1),
we get 200.
So total work/M + B = 200/50 = 4days.
(26M & 48B)2Days > (52M & 96B)...(2).
Subtract 1 And 2 We get 8M & 16B.
Time Taken To Complete the work = Ratio= 2(M):1(B).
Now, (15M & 20B) = ? ...(03).
Put the ratio of 2:1 in (03),
We get 50.
Also put ratio in (1),
we get 200.
So total work/M + B = 200/50 = 4days.
Priya said:
1 decade ago
6x+8y = 1/10.
26x+48y = 1/2.
Multiply Eq first by 5.
30x+40x = 1/2.
26x+48y = 30x+40y from this x = 2y put in eq 1 We get y = 1/200 And x = 1/100.
26x+48y = 1/2.
Multiply Eq first by 5.
30x+40x = 1/2.
26x+48y = 30x+40y from this x = 2y put in eq 1 We get y = 1/200 And x = 1/100.
Deepak said:
1 decade ago
Lets equation 6m + 8b can a work in 10 days .....(1).
If we see that last line of que. We found 15m +20b how much time will taken.
(6m +8b)*2.5, we will get 15m+20b. So we can divide the time taken by equation 1 by 2.5
10/2.5 = 4 DAYS.
If we see that last line of que. We found 15m +20b how much time will taken.
(6m +8b)*2.5, we will get 15m+20b. So we can divide the time taken by equation 1 by 2.5
10/2.5 = 4 DAYS.
Ballu... said:
1 decade ago
Lets try in other way:
Here given 6 and 8 do in 10 days. If persons halved then time doubles.
Then 3 and 4 will do work in 20 days.
By the same way,
If persons double. Then time half's. In the same way.
If 5 times the members. Then 1/5 times the days. Then 15 and 20 will do. Work in 4 days.
Here given 6 and 8 do in 10 days. If persons halved then time doubles.
Then 3 and 4 will do work in 20 days.
By the same way,
If persons double. Then time half's. In the same way.
If 5 times the members. Then 1/5 times the days. Then 15 and 20 will do. Work in 4 days.
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