Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 5 of 21.
Nitesh.s.naik said:
6 years ago
Here 6 men and 8 boys take 10 days to complete the work.
In the same way, 26 men and 48 boys take 2 days to do the same work.
Clearly, by common we can say 1men=2 boys.
So we can covert the no.of men into boys
And by take their one day work and cross multiplying it, we will get the answer.
Therefore =6men*2+8boys=1/10.
And 15men*2+20boys=?.
20=1/10,
50=?,
Therefore, ?=1/4 (one day work).
Total mo of day=4.
In the same way, 26 men and 48 boys take 2 days to do the same work.
Clearly, by common we can say 1men=2 boys.
So we can covert the no.of men into boys
And by take their one day work and cross multiplying it, we will get the answer.
Therefore =6men*2+8boys=1/10.
And 15men*2+20boys=?.
20=1/10,
50=?,
Therefore, ?=1/4 (one day work).
Total mo of day=4.
(1)
Madhura said:
5 years ago
Given :
6M + 8B = 10
26M + 48B = 2
To find 15M + 20M =?
=> Remember :- Worker increases Days decreases.
6*2+3 is 15.
8*2+4 is 20.
4-3= 1,
So 10÷2-1 = 4 days.
6M + 8B = 10
26M + 48B = 2
To find 15M + 20M =?
=> Remember :- Worker increases Days decreases.
6*2+3 is 15.
8*2+4 is 20.
4-3= 1,
So 10÷2-1 = 4 days.
(1)
Devil said:
4 years ago
Thanks for the good explanation @Parkavi.
(1)
Singh said:
2 decades ago
Siddu you are genious friend.
Arun said:
1 decade ago
There must be a faster way of doing this mentally. Like skipping the equation part. Some kind of approximation. Does anyone know?
Bharathi said:
1 decade ago
How 1/100+1/200=4 ?
Nagarjun said:
1 decade ago
@Bharathi.
Hey its not 1/100+1/200=4
Its (15/100)+(20/100)
This vl give 1/4, vch is 1 day's work, and finally they can complete it in 4 days.
Hey its not 1/100+1/200=4
Its (15/100)+(20/100)
This vl give 1/4, vch is 1 day's work, and finally they can complete it in 4 days.
Vicky said:
1 decade ago
2x+3y=1/10 ----- (1)
3x+2y=1/8 ------(2)
we want to find: 2x+1y=?----(3)
any one can solve this
3x+2y=1/8 ------(2)
we want to find: 2x+1y=?----(3)
any one can solve this
Vicky said:
1 decade ago
@Sidhu
We want to find: 15x+20y=?----(3)
now taking 2 common form equ(1),
We get: 2(3x+4y)=1/10
So we have, 3x+4y=1/20...ok...///// if we take 2 common ok
2(3x+4y)ok but how u get = 1/20 hmmmmmm
We want to find: 15x+20y=?----(3)
now taking 2 common form equ(1),
We get: 2(3x+4y)=1/10
So we have, 3x+4y=1/20...ok...///// if we take 2 common ok
2(3x+4y)ok but how u get = 1/20 hmmmmmm
Chetan said:
1 decade ago
Proceed the same way as Meera has done it for Sangeeta.
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