Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 21 of 21.
Balu said:
5 years ago
If X is the overall work then,
X=10(6m+8b)=60m+80b-----1st eqn.
X=2(26m+48b)=52m+96b-----2nd eqn.
Equating the both eqns 1 and 2
We get m:b=1:2 it means 1man equal to 2 boys so 15m+20b=30b+20b=50b.
From eqn 1,12b+8b=20b can do in 10days.
Then cm to 20b=10.
50b=y.
Y=4 days.
X=10(6m+8b)=60m+80b-----1st eqn.
X=2(26m+48b)=52m+96b-----2nd eqn.
Equating the both eqns 1 and 2
We get m:b=1:2 it means 1man equal to 2 boys so 15m+20b=30b+20b=50b.
From eqn 1,12b+8b=20b can do in 10days.
Then cm to 20b=10.
50b=y.
Y=4 days.
Malay said:
5 years ago
Can't understand this 2 equation. Please, anyone, explain.
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