Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
203 comments Page 19 of 21.
Sushil Mishra said:
2 decades ago
Thanks Sidharth, but will you tell me that this types of combination will be the make in every equation mean can we get as simplest way or common part in the each question.
Neha said:
2 decades ago
Siddharth you rock! thanks.
Pavan9966606261 said:
2 decades ago
Hi friends according to my instinct the simplest way was solved by himadri. It keeps our time in tact.
Ragavi said:
2 decades ago
Siddu you are excellent. Please keep help us with your short cutz:).
Rithesh said:
2 decades ago
Siddu I am impressed I hope you continue giving answer like that.
Chandra said:
2 decades ago
So we have, 3x+4y=1/20...ok...
now
in equ 3, take 5 common;
we get:
=5(3x+4y) (3x+4y=1/20)----->//siddu can u explain me this step.
=5*(1/20)
=4 (ans)
now
in equ 3, take 5 common;
we get:
=5(3x+4y) (3x+4y=1/20)----->//siddu can u explain me this step.
=5*(1/20)
=4 (ans)
Rupali said:
2 decades ago
Thank you siddharth. The most simple way to explain the method. :-).
Subrata Dev said:
2 decades ago
Excellent solving. Thanks for nice math solving.
Thanks
Thanks
Pradeep kumar said:
2 decades ago
The solution is being given by you is 100 % satisfying. Thanks to all.
Himadri said:
2 decades ago
This is also easy way friends...
6x+8y=1/10
2(3x+4y)=1/10
3x+4y=1/20
both side multiple with 5
15x+20y=1/4
so 1/4 work complete =1 day
total work=4days
6x+8y=1/10
2(3x+4y)=1/10
3x+4y=1/20
both side multiple with 5
15x+20y=1/4
so 1/4 work complete =1 day
total work=4days
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