Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 18 of 21.
Harish Raj said:
1 decade ago
Here is my approach.
Add the men and boys in each seniario which will be like the following,
6+8= 10 so (14 persons can do the work in 10 days) -- 1
26+48=74 so, (76 persons can do the work in 2 days) --2
now the question is, 20+15 i.e (35 person can do the work in how many days?)
take the second senario,
if 74 person can do the work in 2 days, 35 person do it in approx 4 (less than) days.
There is no Answer given less than 4, s0 we can take 4 as answer. simple. (CAT needs smart work than hard work)
Add the men and boys in each seniario which will be like the following,
6+8= 10 so (14 persons can do the work in 10 days) -- 1
26+48=74 so, (76 persons can do the work in 2 days) --2
now the question is, 20+15 i.e (35 person can do the work in how many days?)
take the second senario,
if 74 person can do the work in 2 days, 35 person do it in approx 4 (less than) days.
There is no Answer given less than 4, s0 we can take 4 as answer. simple. (CAT needs smart work than hard work)
Naman said:
1 decade ago
Bhanu you are genius.
Fantastic approach.
Fantastic approach.
Xyz said:
1 decade ago
Thanks Meera..!!!
Shashank said:
1 decade ago
@Siddhu thanks mate.
Ovii said:
1 decade ago
I have a question from himadri or anyone who can answer this.
What will be the answer if the last line of question be like "25 men and 19 boys in doing the same type of work will be". Then we still continue multipling it by 5 or it has another way?
What will be the answer if the last line of question be like "25 men and 19 boys in doing the same type of work will be". Then we still continue multipling it by 5 or it has another way?
Ovii said:
1 decade ago
Himadri way is good for calculating it mentally!
Surya said:
1 decade ago
Siddu good work man.
Bhanu Chander said:
1 decade ago
(6Men+8Boy).10=(26Men+48Boy).2
solve the above eq
1Men=2Boy
15Men+20Boy=25Men
6men+ 4men=(// 1men=2Boy)
10men ---10days
25men---?
10*10=25*D
D=4days
25men=15men+20boy=4days
solve the above eq
1Men=2Boy
15Men+20Boy=25Men
6men+ 4men=(// 1men=2Boy)
10men ---10days
25men---?
10*10=25*D
D=4days
25men=15men+20boy=4days
Sudha sargam said:
1 decade ago
Hey chandra.
Its lyk 5(3x+4y)/(3x+4y)=?/1/20
So (3x+4y)get cancelled up and down.
and we get....
5=? x 20
so, ?=5/20
?=1/4
So they will complete in 4 days.
Its lyk 5(3x+4y)/(3x+4y)=?/1/20
So (3x+4y)get cancelled up and down.
and we get....
5=? x 20
so, ?=5/20
?=1/4
So they will complete in 4 days.
Sushil Mishra said:
1 decade ago
Thanks Sidharth, but will you tell me that this types of combination will be the make in every equation mean can we get as simplest way or common part in the each question.
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