Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 18 of 21.
Devi said:
8 years ago
Can you please explain in LCM method?
Jigme Wangchuk said:
5 years ago
Can someone explain it in LCM method?
(6)
Prakash said:
1 decade ago
Why Multiply in 1st equation into 6.
Ujjwal said:
9 years ago
How we got 1/10?
Please explain it.
Please explain it.
Suraj said:
8 years ago
Thanks for explaining the solution.
Anup S. said:
8 years ago
@Siddharth.
Very well explained.
Very well explained.
Waseem said:
4 years ago
Thanks for explaining this @Zoya.
(4)
Anton said:
9 years ago
How to get 15/100 + 20/200 = 4?
Mounika said:
8 years ago
Very well explained @Siddharth.
AJAY LAKUM said:
1 decade ago
Thanks sudha good explanation.
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