Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = | ![]() |
15 | + | 20 | ![]() |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 19 of 21.
Gourav Singh said:
9 years ago
14 * 10/35 = 4days
8 + 6 = 14.
8 + 6 = 14.
Ticis said:
7 years ago
Thanks for your answer @Sidhu.
Singh said:
2 decades ago
Siddu you are genious friend.
Bilal khan said:
8 years ago
Please explain 10/100 20/200.
Neha said:
1 decade ago
Siddharth you rock! thanks.
Anee said:
1 decade ago
2x+3y=10, 3x+2y=8, 2x+1y=?
Swati said:
10 years ago
You are genius @Siddharth.
Richa said:
1 decade ago
Hi siddhu! thanks friend.
Divya said:
1 decade ago
Thanks siddu and banu.
Vishal kamdar said:
1 decade ago
Thanks bhanu chander.
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