Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 17 of 21.
Naman said:
1 decade ago
Bhanu you are genius.
Fantastic approach.
Fantastic approach.
Bhagi said:
9 years ago
Can anyone tell formula for this question?
Chandra sekhar reddy said:
8 years ago
Thank you all for explaining the solution.
Manisha said:
8 years ago
Well said. Thank you for this @Siddharth.
Bhavani said:
8 years ago
Thank you for the explanation @Siddharth.
Devil said:
4 years ago
Thanks for the good explanation @Parkavi.
(1)
Rahul said:
10 years ago
How to solve 8y = 4/100, please help me.
Nagendran Periyasamy said:
9 years ago
Can anyone explain that 1/100 and 2/200?
Jyoti said:
1 decade ago
Thanks to give various tricks by all.
Chinna said:
10 years ago
Sir please give a shortcut technique.
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