Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
4 days
5 days
6 days
7 days
Answer: Option
Explanation:

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

Then, 6x + 8y = 1 and 26x + 48y = 1 .
10 2

Solving these two equations, we get : x = 1 and y = 1 .
100 200

(15 men + 20 boy)'s 1 day's work = 15 + 20 = 1 .
100 200 4

15 men and 20 boys can do the work in 4 days.

Discussion:
202 comments Page 14 of 21.

Rupali said:   1 decade ago
Thank you siddharth. The most simple way to explain the method. :-).

Ragavi said:   1 decade ago
Siddu you are excellent. Please keep help us with your short cutz:).

Kumudha said:   1 decade ago
Thank you Siddharth, But is this same way to solve same kind of sum.

Anomii said:   7 years ago
@Sidhu

How you got 1/60=3/5 in that equation? Please explain that.

Mishi said:   10 years ago
I can't understand how 10 days come 1/10? If anyone can explain it?

SS Gour said:   9 years ago
6m + 8b = 10

3m + 4b = 20

Hence,

15m + 25 = 20/5 (4 days, ans)

Rithesh said:   1 decade ago
Siddu I am impressed I hope you continue giving answer like that.

Sangeetha said:   2 decades ago
Can you please solve these 2 equations and show me the result?
(1)

Divya said:   10 years ago
Please solve these equation i.e: 2x+3y = 1/10 and 3x+2y = 1/8.

Muruganantha iyappan said:   10 years ago
In the given answer, how to solve 6x+8y=1/10 AND 26x+48y=1/2?


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