Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = | ![]() |
15 | + | 20 | ![]() |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 14 of 21.
Rupali said:
1 decade ago
Thank you siddharth. The most simple way to explain the method. :-).
Ragavi said:
1 decade ago
Siddu you are excellent. Please keep help us with your short cutz:).
Kumudha said:
1 decade ago
Thank you Siddharth, But is this same way to solve same kind of sum.
Anomii said:
7 years ago
@Sidhu
How you got 1/60=3/5 in that equation? Please explain that.
How you got 1/60=3/5 in that equation? Please explain that.
Mishi said:
10 years ago
I can't understand how 10 days come 1/10? If anyone can explain it?
SS Gour said:
9 years ago
6m + 8b = 10
3m + 4b = 20
Hence,
15m + 25 = 20/5 (4 days, ans)
3m + 4b = 20
Hence,
15m + 25 = 20/5 (4 days, ans)
Rithesh said:
1 decade ago
Siddu I am impressed I hope you continue giving answer like that.
Sangeetha said:
2 decades ago
Can you please solve these 2 equations and show me the result?
(1)
Divya said:
10 years ago
Please solve these equation i.e: 2x+3y = 1/10 and 3x+2y = 1/8.
Muruganantha iyappan said:
10 years ago
In the given answer, how to solve 6x+8y=1/10 AND 26x+48y=1/2?
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