Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 15 of 21.
Nandini said:
1 decade ago
Hi. Siddhu really very nice explanation. Thank you so much.
Sakshi said:
1 decade ago
Guys how this 3/5 is coming please anyone explain solution?
Kartik said:
8 years ago
How did we calculate the value for y=1/200? Please explain.
Vicky said:
8 years ago
How did we calculate the value for y=1/200? Please explain.
Sachin said:
9 years ago
Why it takes 1/10 and 1/2 respectively? Please explain me.
Malay said:
6 years ago
Can't understand this 2 equation. Please, anyone, explain.
Bhargavi namballa said:
1 decade ago
I didn't understand. Could you please explain once again?
Subrata Dev said:
1 decade ago
Excellent solving. Thanks for nice math solving.
Thanks
Thanks
P.swathi said:
1 decade ago
Is there any shot cut formulas to solve x and y values ?
Chetan said:
1 decade ago
Proceed the same way as Meera has done it for Sangeeta.
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