Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
4 days
5 days
6 days
7 days
Answer: Option
Explanation:

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

Then, 6x + 8y = 1 and 26x + 48y = 1 .
10 2

Solving these two equations, we get : x = 1 and y = 1 .
100 200

(15 men + 20 boy)'s 1 day's work = 15 + 20 = 1 .
100 200 4

15 men and 20 boys can do the work in 4 days.

Discussion:
202 comments Page 13 of 21.

Tarak said:   1 year ago
Given:

6M + 8B = 1/10.
10(6M + 8B) = 1,
60M + 80B = 2,
30M + 40B = 3.
15M + 20B = 4.
(80)

SSUMEDH said:   1 decade ago
(6Men+8Boy).10=(26Men+48Boy).2
Solve the above equation
1Men=2Boy
15Men+20Boy=25Men

Zoya said:   1 decade ago
M1*D1/W1 = M2*D2/W2.

14[men + boys]*10 /1 = 35 * D2 /1.

14*10/35 = D2.

D2 = 4.

Suji said:   1 decade ago
@Bavi.
Excellent trick.

@Sutha.
Multiply the term 1/10 also with 6(6/10=3/5).

Aditi said:   10 years ago
Can you tell why we have taken 1/10 days in the above question's equation?

Gopi said:   9 years ago
Thank you so much @Meera, your method is such wonderful for pure solving.

ESNALA SIDDA said:   4 months ago
2(3m+4b) = 1/10,
3m+4b = 1/20,
5(3m+5b) = ?
= 5×1/20,
= 1/4,
= 4days.
(24)

Pradeep kumar said:   1 decade ago
The solution is being given by you is 100 % satisfying. Thanks to all.

Ash said:   9 years ago
I am not getting the solution.

Will anyone solve the equation for me?

Alia said:   9 years ago
@Atul1487.

Your method was awesome! I liked it well, thanks for that.


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