Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
201 comments Page 14 of 21.
Manisha said:
8 years ago
Well said. Thank you for this @Siddharth.
Devi said:
8 years ago
Can you please explain in LCM method?
Bhavani said:
8 years ago
Thank you for the explanation @Siddharth.
Ranjitgh said:
8 years ago
If 10x= 1/10 means. Then x =1, na. How come x=1/100.
Naresh said:
8 years ago
The total work is same if take all men and boys are equal then we can write.
(6+8)*10=(15+20)*x.
By solving x=4.
As we know work =eff*time.
(6+8)*10=(15+20)*x.
By solving x=4.
As we know work =eff*time.
Keshav said:
8 years ago
@Sangeetha.
Please explain this equation and 1/200 how did it come?
6*1/10+8y=1/10.
8y=4/100.
y=1/200.
Please explain this equation and 1/200 how did it come?
6*1/10+8y=1/10.
8y=4/100.
y=1/200.
Bilal khan said:
8 years ago
Please explain 10/100 20/200.
Nandhini said:
7 years ago
Thanks @Meera.
Anurag Chachan said:
7 years ago
Answer will be 5.
Anup S. said:
7 years ago
@Siddharth.
Very well explained.
Very well explained.
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