Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
201 comments Page 13 of 21.
NIRJARA said:
8 years ago
Thanks a lot @Siddhu.
Anamika said:
8 years ago
Hi everyone I didn't understand this.
So please anyone explain it step by step for me.
So please anyone explain it step by step for me.
Arjun said:
8 years ago
This is also easy way friends.
6x + 8y = 1/10,
2(3x+4y) = 1/10,
3x+4y = 1/20,
Both side multiple with 5.
15x + 20y = 1/4,
So 1/4 work complete =1 day,
Total work = 4days.
6x + 8y = 1/10,
2(3x+4y) = 1/10,
3x+4y = 1/20,
Both side multiple with 5.
15x + 20y = 1/4,
So 1/4 work complete =1 day,
Total work = 4days.
Ujjwal said:
8 years ago
How we got 1/10?
Please explain it.
Please explain it.
Vijay said:
8 years ago
Guys. No need to get in to the equation. If 6 man and 8 boys can do a work in 10 days. So obviously 12 men's and 16 boys can complete this in 5 days. (Since the count of the mens and boys is 15 and 20 respectively. So the number of the day will be reduce more. So the only option is 4 which is below 5) so the answer is 4.
Moses said:
8 years ago
Work= men * days.
(6m+8b)*10 = (26m+48b)*2 (since work is same).
By solving above equation, we get "m=2b".
(15m+20b) * days = (6m+8b) * 10,
(30b+20b) *days = (12b+8b) * 10 (since m=2b),
By solving above equation we get,
Days = 4.
(6m+8b)*10 = (26m+48b)*2 (since work is same).
By solving above equation, we get "m=2b".
(15m+20b) * days = (6m+8b) * 10,
(30b+20b) *days = (12b+8b) * 10 (since m=2b),
By solving above equation we get,
Days = 4.
Divya said:
8 years ago
Hi, @Mmeera.
How did you solve this how it will come 3/5 in first equation by multiplying *6?
How did you solve this how it will come 3/5 in first equation by multiplying *6?
Harun Sobbosachi said:
8 years ago
6 men + 8 boys = 10 days -----> (1)
26 men + 48 boys = 2 days -----> (2).
From equation (1) we get,
30 men + 40 boys = 2 days -----> (3)
Given condition,
15 men + 20 boys = ? -----> (4)
Comparing (2) & (3),
4 men = 8 boys, so 1 man = 2 boys.
then for equation (1), 10 men = 10 days.
for equation (4), 25 men = (10x10)25 = 4 days (ans.)
26 men + 48 boys = 2 days -----> (2).
From equation (1) we get,
30 men + 40 boys = 2 days -----> (3)
Given condition,
15 men + 20 boys = ? -----> (4)
Comparing (2) & (3),
4 men = 8 boys, so 1 man = 2 boys.
then for equation (1), 10 men = 10 days.
for equation (4), 25 men = (10x10)25 = 4 days (ans.)
(4)
Kartik said:
8 years ago
How did we calculate the value for y=1/200? Please explain.
Vicky said:
8 years ago
How did we calculate the value for y=1/200? Please explain.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers