Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
A's 2 day's work = | ![]() |
1 | x 2 | ![]() |
= | 1 | . |
20 | 10 |
(A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | + | 1 | ![]() |
= | 6 | = | 1 | . |
20 | 30 | 60 | 60 | 10 |
Work done in 3 days = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
10 | 10 | 5 |
Now, | 1 | work is done in 3 days. |
5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 29 of 36.
Chirag Lakhani said:
2 decades ago
How step 3 is make 1/10+1/10? please explain it.
Preethi said:
1 decade ago
Why we are takng 3*5 in last step please expain.
Raju said:
1 decade ago
Why we are takng 3*5 in last step please expain.
Venkat said:
10 years ago
Please tell me how 3 is coming in the last step?
Vicky said:
10 years ago
Please anyone give clear explanation I confused.
Arpit Mathur said:
1 decade ago
Hey please explain why A's 2 day work is taken?
Hamsa said:
1 decade ago
How did you get 6/60 could you please clarify?
Sudha said:
1 decade ago
Is there any other simple trick to solve this?
Veena said:
8 years ago
Why we add 1/10 and 1/10 here? Please explain.
Gabriel said:
6 years ago
One simple way : 1/20 + (1/90 + 1/180) = 1/15.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers