Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
A's 2 day's work = | ![]() |
1 | x 2 | ![]() |
= | 1 | . |
20 | 10 |
(A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | + | 1 | ![]() |
= | 6 | = | 1 | . |
20 | 30 | 60 | 60 | 10 |
Work done in 3 days = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
10 | 10 | 5 |
Now, | 1 | work is done in 3 days. |
5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 30 of 36.
Karan Singh said:
1 decade ago
Indeed, the explanation of baskar is correct.
Tarun said:
10 years ago
Anyone explain this question with LCM method.
Britney said:
5 years ago
How did we get 6/60? Anyone explain about it.
(1)
Anbu said:
1 decade ago
How you got 6/60?
I think the answer is 12.
I think the answer is 12.
Sindu said:
1 decade ago
Why in the last step 3 is multiplied with 5?
Vani said:
10 years ago
In last step why did they multiplied with 3?
Shashikumar g said:
7 years ago
Nice explanation, Thanks @Shashank Tripathi.
Siddu said:
1 decade ago
Please explain how we will get 6/60 please?
Anonymous said:
1 decade ago
Why do you need to find A's work in 2 days?
Parth said:
10 years ago
What is the Mean assisted in this question?
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