Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
A's 2 day's work = | ![]() |
1 | x 2 | ![]() |
= | 1 | . |
20 | 10 |
(A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | + | 1 | ![]() |
= | 6 | = | 1 | . |
20 | 30 | 60 | 60 | 10 |
Work done in 3 days = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
10 | 10 | 5 |
Now, | 1 | work is done in 3 days. |
5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 31 of 36.
Rizwan said:
8 years ago
How this 2 step comes 1/60? explain please.
Azam rizwan said:
1 decade ago
Why are we multiplying it by 5 in the end?
Dhanam said:
1 decade ago
Why are you taking 2 days for first step?
Satish kumar said:
1 decade ago
How will make step 3 (1/10+1/10) explain?
Lakhan said:
1 decade ago
Why 3 is multiplied by 5 in first method?
Akash said:
10 years ago
Hey why in last we multiplied 1/5 with 3?
Dhara jawale said:
7 years ago
Please explain the second step in detail.
Kumar said:
1 decade ago
Can you please tell me how you get 6/60?
Golu said:
1 decade ago
Why we are calculating 2 days of work A?
Tejeswar Sai said:
7 years ago
Thank you @Vikas, very good explanation.
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