Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
| A's 2 day's work = |  |
1 | x 2 |  |
= | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | |
1 | + | 1 | + | 1 | |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | |
1 | + | 1 | |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 28 of 36.
Garima Yadav said:
1 decade ago
I haven't got it. Can anyone please help me for this?
SRINIVAS said:
9 years ago
How A's 2 day's work = 1/10? Please explain the step.
Sha said:
7 years ago
How does the last step is (3*5=15)?
How come 3 here?
How come 3 here?
Yash said:
8 years ago
Why are we multiplying by 5 for whole work? Explain.
Sangi said:
7 years ago
Why 3 is multiplied with 5 at last?
Please explain.
Please explain.
Vinoth said:
2 decades ago
How do you know total working day is 3 (last step).
(1)
Shreya said:
1 decade ago
I dint get how did you multiply 5*3. It was 1/5 83?
Aiswarya said:
9 years ago
How did we get that 1/10+1/10 ? Can anyone help me?
Karthikeyan said:
1 decade ago
Please explain me the lcm method for this problem.
Shubham said:
8 years ago
Please explain the last step ( 1/10 + 1/10) = 1/5.
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