Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
A's 2 day's work = | ![]() |
1 | x 2 | ![]() |
= | 1 | . |
20 | 10 |
(A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | + | 1 | ![]() |
= | 6 | = | 1 | . |
20 | 30 | 60 | 60 | 10 |
Work done in 3 days = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
10 | 10 | 5 |
Now, | 1 | work is done in 3 days. |
5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 27 of 36.
Kamalakannan said:
1 decade ago
Could you tell me? why you take A has done by 2 days work?
Simita said:
6 years ago
Why 3 is multiplied by 5 in the last step? Please tell me.
Rayhan said:
9 years ago
Good explanation. I really understand this. Thankyou all.
Vijay said:
5 years ago
How we got only A done 3 days of work? Please explain it.
(1)
Munish said:
1 decade ago
Thank you Vikas for your information, I have understood.
Yogendra said:
1 decade ago
Thanks nikithas & bhaskar for your nice explanation.
Siddalingaswamy c said:
1 decade ago
1/20+1/30+1/60=6/60. Can any one say the 6 came in 6/60?
Pawan choudhary said:
1 decade ago
Why the first step I don't understand please explain me?
Puspanjalisahoo said:
9 years ago
I am not understanding A's 2 day's work. Please explain.
Varun said:
1 decade ago
How you can take total working days as 3 in last step?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers