Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
| A's 2 day's work = |  |
1 | x 2 |  |
= | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | |
1 | + | 1 | + | 1 | |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | |
1 | + | 1 | |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 26 of 36.
Pooja Pawatekar said:
5 years ago
How can you take A's 2 days work? Can anyone explain this pls?
Yashraj said:
1 decade ago
(1/20) + (1/30) + (1/60) = 6/60. Please explain me this step.
Manju verma said:
10 years ago
Thank you for the solution its really easy way to understand.
Chaaya said:
1 decade ago
Can anybody explain me why 5 is multiplied by 3 at the end??
Netra said:
1 decade ago
Please tell me why they have multiplied 3 day's work with 5.
Sami said:
1 decade ago
Hi.
Can you explain me that how do you get A's 2 days work?
Can you explain me that how do you get A's 2 days work?
Zyr said:
1 decade ago
1work/5days = 3 days or 1/5=3 then cross multiply to get 15.
Jenni said:
9 years ago
How to multiply and solve this equation?
1/20 + 1/30 + 1/60
1/20 + 1/30 + 1/60
Vijay said:
1 decade ago
1/20+1/(30X3)+1/(60X3) = 1/15
Is my way of solving correct?
Is my way of solving correct?
Poornima said:
1 decade ago
How can you taking that 3 days? and 1/10+1/10 what is it ?
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