Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
| A's 2 day's work = |  |
1 | x 2 |  |
= | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | |
1 | + | 1 | + | 1 | |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | |
1 | + | 1 | |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 25 of 36.
Nitish Mehta said:
1 decade ago
@Liza. What will you do after calculate 6/60?
Complete your answer.
Complete your answer.
Manish Raj said:
7 years ago
A's work = 20,
A+B+C = 10,
Together {A+(A+B+C)}/2 = (30+20)/2 = 15.
A+B+C = 10,
Together {A+(A+B+C)}/2 = (30+20)/2 = 15.
Naren kumar B said:
2 years ago
A = 20,
B = 30,
C = 60.
Find 1/A + ((1/B + 1/C)/3).
= 15 => Answer.
B = 30,
C = 60.
Find 1/A + ((1/B + 1/C)/3).
= 15 => Answer.
(193)
Manasa said:
1 decade ago
@nikita prasad. You just rock. Good explanation with logic. :-) ).
Manju said:
1 decade ago
LCM OF 20, 30, 60 is 60. Work out LCM method that means 10*2*3=60.
Chirag gupta said:
1 decade ago
I read this but understood nothing please explain in easiest way.
Fathi said:
1 decade ago
Awesome explanation nikitha! this is Wat I was searching for:-).
Mareeswari said:
1 decade ago
Sir I can't understand the A is working two days please explain.
Anitha said:
1 decade ago
Why we have to calculate A's days work? Explain any one please.
Vishnu said:
1 decade ago
Why you have taken the a+b+c? A is assisted by only B, C know.
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