Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
12 days
15 days
16 days
18 days
Answer: Option
Explanation:

A's 2 day's work = 1 x 2 = 1 .
20 10

(A + B + C)'s 1 day's work = 1 + 1 +1 = 6 = 1 .
20 30 60 60 10

Work done in 3 days = 1 + 1 = 1 .
10 10 5

Now, 1 work is done in 3 days.
5

Whole work will be done in (3 x 5) = 15 days.

Discussion:
357 comments Page 24 of 36.

Asanka said:   1 decade ago
If x = A worked day

{x*1/20 + x/3*(1/30+1/20)} = 1

x/20+x/60 = 1

x = 15.

Preethu said:   9 years ago
Why do we multiply it by 5?

How we get the answer as 15? Please help me.

Amit yadav said:   8 years ago
Explain the Step 1.

A's 2 day's work = 1/20*2= 1/10. Explain it clearly.

Randheer said:   1 decade ago
Please anyone can explain what formula we have to use for this problems?

Sandhu said:   1 decade ago
Sir I can't understand the calculation of 1\20+1\30+1\60 please tell me.

Deepa said:   8 years ago
Can you explain me how it is 1/5 and 3*15? I'm not getting this concept.

Vivek said:   6 years ago
I can't get 3rd step.

How do 1/10+1/10 came and how it is divided by 5?

Keerthi said:   5 years ago
why are we multiplying 1/5 *3 in the last step? Please explain anyone.

Sundas said:   1 decade ago
I didn't get step 1 how a 2 days work? I mean why we multiply with 2?

Venkat said:   10 years ago
3 = 1/5.

So, our complete work done at 1.

So, 3*5 = 1/5*5.

15 = 1.


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