Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
12 days
15 days
16 days
18 days
Answer: Option
Explanation:

A's 2 day's work = 1 x 2 = 1 .
20 10

(A + B + C)'s 1 day's work = 1 + 1 +1 = 6 = 1 .
20 30 60 60 10

Work done in 3 days = 1 + 1 = 1 .
10 10 5

Now, 1 work is done in 3 days.
5

Whole work will be done in (3 x 5) = 15 days.

Discussion:
357 comments Page 23 of 36.

Ismail said:   9 years ago
Why didn't we take first B + C one day work is 1/30 + 1/60 = 1/20?

Please explain me.

Bond said:   1 decade ago
1/5 of work --->3 days.

1 complete work ---> ?

= (1*3)/(1/5).

= 15 days.

Shreemanjesh said:   5 months ago
A = 20, B = 30, c = 60,
LCM = 60,
A = 3,
b = 2,
C = 1.
A = 3 × 3 = 9 + (abc)6 = 15.
(36)

Ram said:   1 decade ago
Last step:

1/5 work = 3 days.

W/5 = 3d.
W = 3*5d.
W = 15d.

Full work = 15 days.

Shruthi said:   9 years ago
Please explain the 2nd step => (A + B + C) 's 1 day's work.

How it becomes 6/60.

Praveen said:   10 years ago
1/5x100-20 percent work done in 3 days therefore for 100 cross multiply 15 days.

Bhavnesh said:   9 years ago
Hi friends.

I just want to know why we are taking 3 days work for 1/10 + 1/10.

Yoezer said:   5 years ago
3 days 1/5.
6 days 2/5.
9 days 3/5.
12 days 4/5.
15 days 5/5( work completed).

Kv manikanta said:   1 decade ago
How do you say that A's work is 2 days it means how it came 2 (1/20) = 1/10.

TEJAL said:   1 decade ago
I can't understand that how the total work is calculated which is done by A.


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