Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
A's 2 day's work = | ![]() |
1 | x 2 | ![]() |
= | 1 | . |
20 | 10 |
(A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | + | 1 | ![]() |
= | 6 | = | 1 | . |
20 | 30 | 60 | 60 | 10 |
Work done in 3 days = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
10 | 10 | 5 |
Now, | 1 | work is done in 3 days. |
5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 23 of 36.
Ismail said:
9 years ago
Why didn't we take first B + C one day work is 1/30 + 1/60 = 1/20?
Please explain me.
Please explain me.
Bond said:
1 decade ago
1/5 of work --->3 days.
1 complete work ---> ?
= (1*3)/(1/5).
= 15 days.
1 complete work ---> ?
= (1*3)/(1/5).
= 15 days.
Shreemanjesh said:
5 months ago
A = 20, B = 30, c = 60,
LCM = 60,
A = 3,
b = 2,
C = 1.
A = 3 × 3 = 9 + (abc)6 = 15.
LCM = 60,
A = 3,
b = 2,
C = 1.
A = 3 × 3 = 9 + (abc)6 = 15.
(36)
Ram said:
1 decade ago
Last step:
1/5 work = 3 days.
W/5 = 3d.
W = 3*5d.
W = 15d.
Full work = 15 days.
1/5 work = 3 days.
W/5 = 3d.
W = 3*5d.
W = 15d.
Full work = 15 days.
Shruthi said:
9 years ago
Please explain the 2nd step => (A + B + C) 's 1 day's work.
How it becomes 6/60.
How it becomes 6/60.
Praveen said:
10 years ago
1/5x100-20 percent work done in 3 days therefore for 100 cross multiply 15 days.
Bhavnesh said:
9 years ago
Hi friends.
I just want to know why we are taking 3 days work for 1/10 + 1/10.
I just want to know why we are taking 3 days work for 1/10 + 1/10.
Yoezer said:
5 years ago
3 days 1/5.
6 days 2/5.
9 days 3/5.
12 days 4/5.
15 days 5/5( work completed).
6 days 2/5.
9 days 3/5.
12 days 4/5.
15 days 5/5( work completed).
Kv manikanta said:
1 decade ago
How do you say that A's work is 2 days it means how it came 2 (1/20) = 1/10.
TEJAL said:
1 decade ago
I can't understand that how the total work is calculated which is done by A.
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