Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
12 days
15 days
16 days
18 days
Answer: Option
Explanation:

A's 2 day's work = 1 x 2 = 1 .
20 10

(A + B + C)'s 1 day's work = 1 + 1 +1 = 6 = 1 .
20 30 60 60 10

Work done in 3 days = 1 + 1 = 1 .
10 10 5

Now, 1 work is done in 3 days.
5

Whole work will be done in (3 x 5) = 15 days.

Discussion:
357 comments Page 22 of 36.

Nandha said:   1 decade ago
@Ajit.

A do a work two days independently, so (1/20+1/20) = 1/10 instead of they taken (1/20*2).

Beeribrahim said:   1 decade ago
How it is user
Now, 1 work is done in 3 days.
5
Whole work will be done in (3 x 5) = 15 days.

Neha Sharma said:   1 decade ago
Why you are multiply 3*5? And in third step why 1/10 is taken in two times? Please exlain it?

Rajasekhar said:   1 decade ago
The question does'nt mean to find the 3 days work how we can solve this for 3 days work?.

Trinadh said:   1 decade ago
1/20, 1/30, 1/60.

Add 1/3 to the ends of both B and C.

= 1/20+1/30*3+*1/60*3.

= 1/15.

BINDU said:   1 decade ago
Here 1/5 is calculated considering ABC together but here we have to fine work done by A?

Sindhu said:   1 decade ago
@Baskar

Can you please explain me why do you cross multiply at the end for the answer?

Priti said:   1 decade ago
We have already calculate 1/5 for 3 days. Then why again multiplying by 3? please help.

Manoj said:   1 decade ago
i.e;

3 days =1/5

6 days=2/5

9 days=3/5

12 days=4/5

15 days=5/5(1)==work completed
(1)

Varinder Singh said:   1 decade ago
Guys I want know that in last step why did the multiplied 5 and three. Please explain.


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