Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 5)
5.
A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?
Answer: Option
Explanation:
| C's 1 day's work = | 1 | - |  |
1 | + | 1 |  |
= | 1 | - | 7 | = | 1 | . |
| 3 | 6 | 8 | 3 | 24 | 24 |
| A's wages : B's wages : C's wages = | 1 | : | 1 | : | 1 | = 4 : 3 : 1. |
| 6 | 8 | 24 |
 C's share (for 3 days) = Rs. |
|
3 x | 1 | x 3200 | |
= Rs. 400. |
| 24 |
Discussion:
179 comments Page 8 of 18.
Kumar said:
1 decade ago
The question is actually not clear. Its should say A, B and C undertook the work for Rs.3200. The questions as it is stated may imply that A and B took Rs.3200 individually. Correct me if I'm wrong.
Nisha said:
1 decade ago
Ya The question is actually not clear. Its should say A, B and C undertook the work for Rs. 3200. The questions as it is stated may imply that A and B took Rs. 3200 individually. Correct me if I'm wrong.
Divakar said:
1 decade ago
Last step can be written as C's share = 1/8*3200 = 400.
DumbAss said:
1 decade ago
Please help.
Where did the number 8 come from in 1/8*3200 = 400?
Where did the number 8 come from in 1/8*3200 = 400?
Pavithra said:
1 decade ago
Can anyone say how the 1/6+1/8 comes as 7/24?
I need the clear explanation of the solution.
I need the clear explanation of the solution.
Sapna said:
1 decade ago
1/6+1/8 = 8+6/48.
= 14/48.
= 7/24.
= 14/48.
= 7/24.
Uday said:
1 decade ago
Suppose if we want A share, then.
A/(A+B+C)*3200 = 4/(4+3+1)*3200.
= 4/8*3200.
A's share = 1600.
B's share = B/(A+B+C) = 3/(4+3+1)*3200.
= 3/8*3200.
B's share = 1200.
Similarly C's share = 400.
Therefore Sum of shares of A+B+C = 3200.
A/(A+B+C)*3200 = 4/(4+3+1)*3200.
= 4/8*3200.
A's share = 1600.
B's share = B/(A+B+C) = 3/(4+3+1)*3200.
= 3/8*3200.
B's share = 1200.
Similarly C's share = 400.
Therefore Sum of shares of A+B+C = 3200.
Kanmani Roja said:
1 decade ago
Another method to solve this problem can be:
A's 1 day work = 1/6.
B's 1 day work = 1/8.
Both combined (1 day work) = 1/6+1/8 = 7/24 work.
Hence both together completed in = 24/7 days.
Therefore in 24/7 days = 3200 wages.
C's working days = 3-24/7 = 3/7.
Hence for 24/7 days = 3200 wages.
C's 3/7 days = x wages.
To find x:
24/7(x) = 3/7*3200.
x = 400.
C should be paid by Rs.400.
A's 1 day work = 1/6.
B's 1 day work = 1/8.
Both combined (1 day work) = 1/6+1/8 = 7/24 work.
Hence both together completed in = 24/7 days.
Therefore in 24/7 days = 3200 wages.
C's working days = 3-24/7 = 3/7.
Hence for 24/7 days = 3200 wages.
C's 3/7 days = x wages.
To find x:
24/7(x) = 3/7*3200.
x = 400.
C should be paid by Rs.400.
Anjana S Babu said:
1 decade ago
A's 1 day work = 1/6.
B's 1 day work = 1/8.
C's 1 day work = 1/3.
We can calculate both A+B = 1/6+1/8.
= 8+6/48 = 14/48.
= 7/24.
Then C's 1 day work = 1/3-7/24.
= 24-21/72 = 3/72.
= 1/24.
B's 1 day work = 1/8.
C's 1 day work = 1/3.
We can calculate both A+B = 1/6+1/8.
= 8+6/48 = 14/48.
= 7/24.
Then C's 1 day work = 1/3-7/24.
= 24-21/72 = 3/72.
= 1/24.
Ram said:
1 decade ago
I think this is a wrong question. In it the information is not given that for how many days A and B are given 3200?
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