Aptitude - Time and Work - Discussion

Option A is the right answer if you perfectly have understood the question.
Here in the question, it is given that A & B undertook to do the work for 3200 then how C can earn his wages from the first day.
Here Supposed A & B if do the work in 3 days then they will able to do - 21 work
But they did it in 3 days with the help of C.

So the method is here that;
For the first two days, A+B do - 14 work.
Then with the help of C they able to finish it in 3 days so A+B+C do last day - 10 work.
That means one-day work of C is - 3.
Then the work ratio of A+B for two days with A+B+C in one day is - 14:10 = 7:5.
Then (3200 ÷12) * 5 = 1250.
Then bye one-day work ratio of A B&C = 4:3:3.
Then (3200÷10) * 3 = 375,
Hence the answer is 375.

@all.

A takes 6 days to complete the job. So a one day work is 1/6 and for 3 days it is 3/6 ie 1/2.

Similarly for B for 3 days work is 3/8 now A's share is 1/2 of 3200= 1600 B's share 3/8 of 3200=1200.

So C's share 3200--- (1600+1200) = 40.

Thank you @Sai vinay.

The sum of three numbers is 275. If the ratio between the fast and second be 3:7 and that between the second and third be 4:5 then find the second number. Can anyone solve this?

1/6 * 24 : 1/8 * 24 :1/24 * 24 convert fraction to the whole number.

What is the need of ratio?

A = 6days.
B = 8days.

A+B+C=3days.
C's no of days required to complete the work.
(1÷6)+(1÷8)+(1÷C)=(1÷3).
Therefore C=24 day's.

Now the ratio of no of days taken by each member to complete the work comes(6:8:24).

But, we know that A is somewhat a fast worker than B and C therefore he must be paid more and C is taking more time he must be paid less,

Now let's considers these people's each day of work ie A=(1÷6), B=(1÷8), C=(1÷24).

Therefore the total units of work=(1÷6)+(1÷8)+(1÷24)=( 1÷3) by taking lcm
Now ,

The total amount to is 3200.
3200/(1÷3)=9600.
Therefore 9600/24 is 400.

Thanks @Shivani Kumari.

1/6+1/8+1/x= 1/3.
=> 1/x= 1/3- 1/6-1/8.
=> 1/x= 1/24,
=> x= 24.

4:3:1.
C's share = Rs. 400.