Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes |  |
3 | x 60 |  |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | |
1 | + | 1 | |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
 A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
281 comments Page 9 of 29.
Nagu said:
2 decades ago
Hi Bharathi,
If A takes 10 days to complete a work means
A's one day work is 1/10
so complete this work A takes 10/1 days is same as 10 days
Sat the same way (A + B)'s 1 day's work 2/45 means
They will take 45/2 = 22 1/2 days
I think you got my point
have a nice day
If A takes 10 days to complete a work means
A's one day work is 1/10
so complete this work A takes 10/1 days is same as 10 days
Sat the same way (A + B)'s 1 day's work 2/45 means
They will take 45/2 = 22 1/2 days
I think you got my point
have a nice day
Ankita said:
1 decade ago
If B takes y days , A takes (y-60 ) days. Now , their efficiency are A:B = 3x : x.
So total unit of work is 3x*(y- 60 ) man days = x*y man days.
Calculating this we get y = 90. So if B worked for 90 days, A worked for 30 days.
Hence 1/30 + 1/90 = 22 1/2 days :).
So total unit of work is 3x*(y- 60 ) man days = x*y man days.
Calculating this we get y = 90. So if B worked for 90 days, A worked for 30 days.
Hence 1/30 + 1/90 = 22 1/2 days :).
Ravi yadav said:
10 years ago
Let A takes x days and B takes y days to complete work. In one day A completed 1/x part of work and B 1/yth.
According to question 1/x = 3*1/y and y-x = 60.
By solving x=30 and y= 90.
So in one day both completed (1/x + 1/y) = 4/90.
They can do it in = 90/4 = 45/2.
According to question 1/x = 3*1/y and y-x = 60.
By solving x=30 and y= 90.
So in one day both completed (1/x + 1/y) = 4/90.
They can do it in = 90/4 = 45/2.
Srinivas said:
1 decade ago
Hi friends,
Given A:B=1:3
Therefore B=3A--------equation 1
let B can do a work in x days.
then A can do the same work in (x-60) days.
then B=3A
x=(x-60)3
therefore x=90 days
therefore B can do a work in 90 days.
and A will do a work in 90-60=30 days.
Given A:B=1:3
Therefore B=3A--------equation 1
let B can do a work in x days.
then A can do the same work in (x-60) days.
then B=3A
x=(x-60)3
therefore x=90 days
therefore B can do a work in 90 days.
and A will do a work in 90-60=30 days.
Mohin Uddin Mizan said:
9 years ago
Let B takes X days to the work.
Then B's 1 day's work = 1/x and A's 1/3x.
ACQ, 1/x - 1/3x = 60, So, x = 1/90.
As the difference is 60, so A needed 90 - 60 = 30 days.
(A + B)'s 1 day's work = 1/90 + 1/30 = 2/45.
So, to do the total work they need 45/2 or 22(1/2).
Then B's 1 day's work = 1/x and A's 1/3x.
ACQ, 1/x - 1/3x = 60, So, x = 1/90.
As the difference is 60, so A needed 90 - 60 = 30 days.
(A + B)'s 1 day's work = 1/90 + 1/30 = 2/45.
So, to do the total work they need 45/2 or 22(1/2).
Nitin Singla said:
1 decade ago
Hey its simple to understand.
Days taken by B = x
Days taken by A= x - 60
Their time taken proportio is 1:3
so,
x - 60/ x = 1/3
x=90;
So A will do the work in = 30 days
abd B in 3x= 3*30=90 days,
and u can find their 1 day's work and ad it.
Simple :)
Days taken by B = x
Days taken by A= x - 60
Their time taken proportio is 1:3
so,
x - 60/ x = 1/3
x=90;
So A will do the work in = 30 days
abd B in 3x= 3*30=90 days,
and u can find their 1 day's work and ad it.
Simple :)
Muhammad said:
4 years ago
Let A's total work completion time be = n.
B's total work completion time = 3n,
Difference between B and A's daily work = 60.
3n - n = 60,
2n = 60.
n = 30.
Total daily work.
=1/3n + 1/n,
=1/90 + 1/30,
=2/45,
So total time to complete for both = 45/2 = 22.5.
B's total work completion time = 3n,
Difference between B and A's daily work = 60.
3n - n = 60,
2n = 60.
n = 30.
Total daily work.
=1/3n + 1/n,
=1/90 + 1/30,
=2/45,
So total time to complete for both = 45/2 = 22.5.
(12)
Showry said:
1 decade ago
Hi Friends,
A:B=1:3 time taken.........since A is 3 good as B
A takes 60 days less than B
B-60:B=1:3............
i.e B-60/B=1/3..... B=90 days.... A=30......
(A+B)'s one day work (1/30+1/90) = (2/45)
Total work by (A+B) is 45/2 i.e 22 1/2.............
A:B=1:3 time taken.........since A is 3 good as B
A takes 60 days less than B
B-60:B=1:3............
i.e B-60/B=1/3..... B=90 days.... A=30......
(A+B)'s one day work (1/30+1/90) = (2/45)
Total work by (A+B) is 45/2 i.e 22 1/2.............
Hari said:
9 years ago
A:B = 3:1 efficiency.
Because, A is Thrice the work as B.
So, A complete the work 60 days before.
Then 2---60
1--30,
So to find total work we just take it as;
A = 3 * 30. B = 1 * 30.
Total work is 90(LCM IS 90).
So, W = ED,
D = 90/4
= 22.5.
Because, A is Thrice the work as B.
So, A complete the work 60 days before.
Then 2---60
1--30,
So to find total work we just take it as;
A = 3 * 30. B = 1 * 30.
Total work is 90(LCM IS 90).
So, W = ED,
D = 90/4
= 22.5.
Suhas Wankhede said:
2 years ago
Given Equation
A = 3B ---> (i)
Let B=x days --> (ii)
Given:
A = x - 60 days ---> (iii)
Compare i and iii;
x-60 = 3B (i.e B=x).
x-60 = 3x,
x = 30.
A = 3 * 30 = 90 days.
B = 30 days.
LCM 90.
A's Efficiency 1.
b's Efficiency 3.
90/3+1 = 22 1/2 days.
A = 3B ---> (i)
Let B=x days --> (ii)
Given:
A = x - 60 days ---> (iii)
Compare i and iii;
x-60 = 3B (i.e B=x).
x-60 = 3x,
x = 30.
A = 3 * 30 = 90 days.
B = 30 days.
LCM 90.
A's Efficiency 1.
b's Efficiency 3.
90/3+1 = 22 1/2 days.
(64)
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