Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes |  |
3 | x 60 |  |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | |
1 | + | 1 | |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
 A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
281 comments Page 7 of 29.
Nishant said:
1 decade ago
@ G.P.
Thanks. I like the way you solve it.
Thanks. I like the way you solve it.
Balaji said:
1 decade ago
Showry you explained superbly.
Prathyusha said:
1 decade ago
SIMPLE AND NICE EXPLANATION!... @KUMAR
Vani said:
1 decade ago
Showry's explanation is good.
Hindu said:
1 decade ago
Hai sheetal your shortcut method helps lot to understand so quickly its really super.
Naveen kumar said:
1 decade ago
Hi friends, Here is a simple technique to calculate the above problem....
Given,
If the If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes......?
We can represent the above relation like this,
2------->3
60------>....?
By cross multiplying the above terms we will get... 60*3/2 = 90.
Note:- Always individual term should come in the denominator.
By applying the above procedure you can solve any problem of this type....
I think this technique will help you while doing with this type of problems...
Given,
If the If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes......?
We can represent the above relation like this,
2------->3
60------>....?
By cross multiplying the above terms we will get... 60*3/2 = 90.
Note:- Always individual term should come in the denominator.
By applying the above procedure you can solve any problem of this type....
I think this technique will help you while doing with this type of problems...
Abdul said:
1 decade ago
Hey Siva your way of solving is fantastic and understandable! Thanks.
Jezan said:
1 decade ago
According to this question if A is x, B will be x+60
1/3=x/x+60
3x=x+60
2x=6
x=30
A+B'S ONE DAY WORK=1/30+1/90=2/45
SO WHOLE WORK S= 45/2( UPSIDE DOWN)
22.5 DAYS.
HOPE ALL LL GET DIS
1/3=x/x+60
3x=x+60
2x=6
x=30
A+B'S ONE DAY WORK=1/30+1/90=2/45
SO WHOLE WORK S= 45/2( UPSIDE DOWN)
22.5 DAYS.
HOPE ALL LL GET DIS
Jaswinder Singh said:
1 decade ago
Ratio of times taken by A and B = 1 : 3. or 1x:3x
so, we say
3x-1x=60,
2x=60,
x=30, so A will 30 day to complected a work,
B will be complete the work ie 3x, 3(30)=90days,
(A+B) 1 Day work = (1/30 + 1/90)
by solving we get,
A+B 1 Day work = 2/45,
so A and B together can complete work in 45/2 Days.
so, we say
3x-1x=60,
2x=60,
x=30, so A will 30 day to complected a work,
B will be complete the work ie 3x, 3(30)=90days,
(A+B) 1 Day work = (1/30 + 1/90)
by solving we get,
A+B 1 Day work = 2/45,
so A and B together can complete work in 45/2 Days.
Sharan said:
1 decade ago
@Jaswinder singh: I understood your explanation man. Thanks.
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