Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
20 days
22 1 days
2
25 days
30 days
Answer: Option
Explanation:

Ratio of times taken by A and B = 1 : 3.

The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.

If difference of time is 2 days, B takes 3 days.

If difference of time is 60 days, B takes 3 x 60 = 90 days.
2

So, A takes 30 days to do the work.

A's 1 day's work = 1
30

B's 1 day's work = 1
90

(A + B)'s 1 day's work = 1 + 1 = 4 = 2
30 90 90 45

A and B together can do the work in 45 = 22 1 days.
2 2

Discussion:
281 comments Page 5 of 29.

Nagu said:   2 decades ago
Hi Bharathi,

If A takes 10 days to complete a work means
A's one day work is 1/10

so complete this work A takes 10/1 days is same as 10 days

Sat the same way (A + B)'s 1 day's work 2/45 means

They will take 45/2 = 22 1/2 days

I think you got my point

have a nice day

SHEETAL said:   2 decades ago
Hi Guys,

Don't be confused in data given in question.

I have one short cut to solve such kind of question.

A is K times as good a worker as B & takes X days less than B to finish the work. Then the amount of time required by A & B working together is K * X / K'S SQUARE - 1.

SO IN QUESTION K IS 3. X IS 60. SO PUTTING THE VALUES IN ABOVE MENTIONED FORMULA.

K * X / K'S SQUARE - 1
=3 * 60 / 9 - 1
=3 * 60 / 8
=180 / 8
=22.5 DAYS

AS MENTIONED OPTION B.

I HOPE U WILL UNDERSTAND THIS THING & WILL APPLY IN QUESTION BASED ON THIS.

All the best. Have nice day!

Sangeetha said:   2 decades ago
Oh thanks sheetal

Prashant said:   1 decade ago
Suppose B takes x days to finish the work and then according to question A will take (60-x) days to work. in question the ratio of time taken is 1:3 therefore

1/3= (60-x)/x
x=45

So A can complete the work in (60-x)=(60-45)=15 days

So (A+B) one day's work
=(1/15 + 1/45)
=4/45

So (A+B) complete the work in 45/4 = 11 1/4 days.

Sugumaran said:   1 decade ago
Ratio of time taken=1:3

A finish the work in 60 days and B in x days.

1:3::60:x
x=180 days

So,

A and B 1'days work 1/60+1/180=45 days

Is it correct or not?

M.Atul said:   1 decade ago
@Sugumaran please read carrefully problem. Though you have got same answer but it doesn't satisfied second condition that differnce in day should be 60 not 120.

Priya said:   1 decade ago
Please tell me why we are taking 3/2 to multiply with 60. Please explin me.

Harsha said:   1 decade ago
A clear approach:

Given: A's time taken:B's time taken=1:3

So A's proportion of time taken=1/(1+3)=>1/4*some x
B's proportion of time taken=3/(1+3)=>3/4*some x

As it is said that difference of time is 60 days

B's time-A's time=60
=> 3x/4-x/4=60
=>x=120

So A's proportion of time taken =x/4=120/4=30 days
B's proportion of time taken =3x/4=3*120/4=90 days

A's 1 day's work = 1/30
B's 1 day's work = 1/90
(A + B)'s 1 day's work = (1/30 + 1/90)= 4/90=2/45

A and B together can do the work in 45/2 = 22 1/2 days.

Naveen said:   1 decade ago
Hi, in prashanth answer, he equals the ratio 1/3 to 60-x/x but it actually x-60/x.

Shilpi said:   1 decade ago
Can you pls teach me this equation
1/30+1/90=4/90


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