Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
20 days
22 1 days
2
25 days
30 days
Answer: Option
Explanation:

Ratio of times taken by A and B = 1 : 3.

The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.

If difference of time is 2 days, B takes 3 days.

If difference of time is 60 days, B takes 3 x 60 = 90 days.
2

So, A takes 30 days to do the work.

A's 1 day's work = 1
30

B's 1 day's work = 1
90

(A + B)'s 1 day's work = 1 + 1 = 4 = 2
30 90 90 45

A and B together can do the work in 45 = 22 1 days.
2 2

Discussion:
284 comments Page 20 of 29.

Sanchi said:   1 decade ago
Very simple way.
3A=1B
B takes x days.
3 (x-60) =x
3x-x=180
X dats is B=90, A=30.
Now,
1/90+1/30=22. 5.

Naresh said:   1 decade ago
1:3.

Total 4 parts.

90/4=22.5 (one part).

Here one part means A's work. Remaining 77.5 belongs to B.

Jack said:   8 years ago
Can anyone explain me why the step 3/2*60 used. I couldn't get the logic of finding difference as 2.

TABISH said:   1 decade ago
@sheetal
do not able to understand how you get that formula to calculate the time i.e.
K*X/K^2-1

Priya said:   7 years ago
The solution is;

A = x ,
B = 3x
x = 3x-60
x = 30
A = 30; B = 90;
1/30 + 1/90 = 2/45 = 22.5 days.

Sumit said:   1 decade ago
If difference of time is 60 days, B takes 3/2 x 60 = 90 days.

Please explain this statement.

Abhijith said:   6 years ago
Can someone provide a solution for this problem using percentages or the efficiency ration ?

Sundar said:   1 decade ago
If difference of time is 60 days 3*60/2 = 90 days.

I can't get this step?

Please explain.

Biplab sarkar said:   8 years ago
Here given k=3, n=60.

So formula is -> kn/ (k^2-1) =3*60/ (3^2-1) =180/8=22 1/2 days.

Billal Hossain said:   5 years ago
x : 3x.
3x - x = 60,
=> 2x = 60,
=> x = 30,
1/30 + 1/90,
= 4/90.
= 22 (1/2).


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