Aptitude - Time and Work - Discussion

Let A takes x days to do the work alone
Therefore days taken by b is (x+60).

Now A is 3 times faster than B
So no.of days taken by A will be 3 times less than B.
So
3*x=(x+60)
2x=60
x=30 days //work done by A
Work done by B=30+60=90 days.

Now we can find work done together
1/30 +1/90 to get the answer.

We have a direct formula for these kind of questions .. i.e.,

Work done together is given by = (m*d)/(m^2 - 1),

Where d is no of days taken by B and m is no of time A is faster than B,
Therefore = (3*60)/(3^2-1) = 22.5.

@All.

Please refer to Sheetal's response as given below. Its the best and easiest way to solve such questions.

PS:Thanks sheetal.

"A is K times as good a worker as B & takes X days less than B to finish the work. Then the amount of time required by A & B working together is K * X / K'S SQUARE - 1.

SO IN QUESTION K IS 3. X IS 60. SO PUTTING THE VALUES IN ABOVE MENTIONED FORMULA.

K * X / K'S SQUARE - 1
=3 * 60 / 9 - 1
=3 * 60 / 8
=180 / 8
=22.5 DAYS.

AS MENTIONED OPTION B.

Simple way:

A and B ratio 1:3.

Since A finishes 60 days lesser than be A takes 90 days and B takes 30 days.

So per day calculation (1/90+1/30) = 22.5 days.

If A is thrice as good as workman B,
Than A=3B ----(1) or B=A/3 --------(2).

If A is finish a job in 60 days less than B.
Than A = B-60.

Put the value of B from Eq.(2).

A = A/3 -60
3A = A-180
2A = 180
than A = 90 Days.

Same Put the value of A in Eq.(2).
B=90/3 = 30 Days.

So Working together (A+B) = 1/90 + 1/30.

A+B = 2/45.
or A+B =45/2 = 22.5 or 22 1/2.

Answer.22 1/2 Days.

Simple yaar.

>A is thrice as good as workman as B and therefore is able to finish a job in 60 days=IF B TAKE 90 DAYS THEN A WILL TAKE 30 (60 DAYS LESS).

>1/30 (PLUS) 1/60=4/90==>90/4==>22. 5 SIMPLE.

Simple method:

Say B completes the work in 'x' days.

Then A will take (x-60) days to finish the work.

Since A is thrice as good as B, 3A=B.

Therefore, 3 (x-60) =x, x=90.

B's 1 day work=1/90, A's 1 day work=1/30.

(A+B) 's 1 day work= (1/90+ 1/30) =2/45.

Therefore, both can finish the work in 45/2 days i.e., 22 1/2.

A is twice as good as workman B and together they finish a piece of work in 14 days. A alone can finish the work in.

Did they mention that difference of working time is 60 days.

In the given question the ration of capacity of work in day a:b is = 3:1.

So always inverse proportion to capacity and work like the way a and b can do the work ration =1:3 i.e. a's one day work = b's three days work.

So let now finish work together is imagine x.

Ratios of each person a's work = x* 1/4 = X/4. (1).

Ration of b's work = x* 3/4 = 3X/4. (2).

In the given question difference is 60 days.

So 3X/4-X/4 = 60 Days.

Solove ther x we get x = 120.

Now substitute x in (1) and (2).

W e get a's part of one day work = 30 days.

And b's part of one day work = 90 days.

Now solve the.

A and B together work = 1/30+1/90 = 4/90 =2/45.

This is and b together part of work now one day work = 45/2 = 22.5 days.