Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes |  |
3 | x 60 |  |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | |
1 | + | 1 | |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
 A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
283 comments Page 10 of 29.
Varma said:
1 decade ago
Nice formula @Sheetal.
Aarush said:
1 decade ago
Thanks sheetal.
TABISH said:
1 decade ago
@sheetal
do not able to understand how you get that formula to calculate the time i.e.
K*X/K^2-1
do not able to understand how you get that formula to calculate the time i.e.
K*X/K^2-1
Raman(UIET,KUK) said:
1 decade ago
Guys check this out and don't be confused....
as we know A is 3 time better than B and A takes 60 days less than B so, time taken by A: time taken by B= 1:3
= b-60:b ( suppose time by B is b)
by cross multiply, 3b-180=b
i.e. b=90 so time taken by B=90
and time taken by the A is=90-60= 30
as we know A is 3 time better than B and A takes 60 days less than B so, time taken by A: time taken by B= 1:3
= b-60:b ( suppose time by B is b)
by cross multiply, 3b-180=b
i.e. b=90 so time taken by B=90
and time taken by the A is=90-60= 30
Kapil said:
1 decade ago
Nic Explanation. . .Sheethal. . .
Shro said:
1 decade ago
Indhu very easy simple explanation as per the question.
Good :) thanku :)
Good :) thanku :)
Sindhu said:
1 decade ago
HI,
This method I feel to be quiet easier.
A is thrice as good as workman as B.
therfore,
A=3B -(1)
finish a job in 60 days less than B
1/B=60+1/A -(2)
i.e B`s One day work = A`s one day work + 60 days.
Solve (1) & (2)
we will get
A= 90;
From (1)
B=A/3
=> B= 30.
(A+B)`s 1 day work = 1/90+1/30
=2/45
=22 1/2 days
This method I feel to be quiet easier.
A is thrice as good as workman as B.
therfore,
A=3B -(1)
finish a job in 60 days less than B
1/B=60+1/A -(2)
i.e B`s One day work = A`s one day work + 60 days.
Solve (1) & (2)
we will get
A= 90;
From (1)
B=A/3
=> B= 30.
(A+B)`s 1 day work = 1/90+1/30
=2/45
=22 1/2 days
Iyappan said:
1 decade ago
Naveen kumar your explanation is beautiful for me.
Sanchi said:
1 decade ago
Very simple way.
3A=1B
B takes x days.
3 (x-60) =x
3x-x=180
X dats is B=90, A=30.
Now,
1/90+1/30=22. 5.
3A=1B
B takes x days.
3 (x-60) =x
3x-x=180
X dats is B=90, A=30.
Now,
1/90+1/30=22. 5.
Nitin singh parihar said:
1 decade ago
Let B do the work in 'x' days.
So, A will take (x-60) days.
Now, ratio of A:B=1:3 (given in ques).
So, 1/3=x-60/x.
=> x=90 (B's 1 day work).
So, A's work=30 days.
Working together=1/30+1/90.
=45/2 days.
Easy and simple.
So, A will take (x-60) days.
Now, ratio of A:B=1:3 (given in ques).
So, 1/3=x-60/x.
=> x=90 (B's 1 day work).
So, A's work=30 days.
Working together=1/30+1/90.
=45/2 days.
Easy and simple.
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