Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
20 days
22 1 days
2
25 days
30 days
Answer: Option
Explanation:

Ratio of times taken by A and B = 1 : 3.

The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.

If difference of time is 2 days, B takes 3 days.

If difference of time is 60 days, B takes 3 x 60 = 90 days.
2

So, A takes 30 days to do the work.

A's 1 day's work = 1
30

B's 1 day's work = 1
90

(A + B)'s 1 day's work = 1 + 1 = 4 = 2
30 90 90 45

A and B together can do the work in 45 = 22 1 days.
2 2

Discussion:
281 comments Page 10 of 29.

Sundar said:   1 decade ago
Please Tell me how 3/2 has come?

Atul1487 said:   1 decade ago
What is need to take time difference?

How will I come to know that I need to calculate time difference?

Venkatesh said:   1 decade ago
Hi friends just read, A's works 3 times than B so work ration 3:1 and time ratio will be 1:3 in the question they ask for time so 3/(3-1)*60=90.

A 3 times better 3/90=1/30(1 days work) B 1/90 1days work together 1/90+1/30=answer.

Poornachandran said:   1 decade ago
Guys,

I'll tell by simple method.
Given, A is thrice of B.

So A = 3B---->(1).
A's 1 day work is A=1/60--->(2).

Substitute (2) in (1),
A=3B.
We get,
3B=1/60.
B=1/180.

In question they asked A+B=how many working days?
We know A and B values.

Add A and B.
1/60+1/180=1/Work days.
Take L.C.M.

3+1/180=1/Work days.
4/180=1/work days.
1/45=1/work days.
Work days=45.

By fraction we can write 22 1/2 days.

Kumar said:   1 decade ago
How its "4/90 " ?

Nithya said:   1 decade ago
Lets B takes x days to complete the Work,

Then B 's Capacity ==>1/x.
A is 3 times as good as A so A'S capacity is 3/x.

Then Time Taken by B is = x/1.
Time taken by A is = x/3.

Time difference (x-x/3)=60.

Which gives x = 90.
Time taken By B = 90.
Time taken By A = 30.

(A's Work +B's Work) 1 day Work = (1/30)+(1/90).
= 4/90.

Then Time taken to complete work is 90/4 ==> 22.5 days.

Pranay said:   1 decade ago
The work being done by A & B is in ratio of 1:3.

This means if A does a work in 1 day, than B will do this work in 3 days.

Now let suppose this ratio is multiplied by a factor, say x.

Then ratio becomes x:3x.

Now another relation given is that A can do work 60 days faster then B. Mathematically we can write it as.

x=3x-60.

Solving this, we get x = 30.

Hence the ratio becomes 30:60.

Now we can calculate the time taken by them.

Thaha said:   1 decade ago
"A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B."

Solution:
*********
'A' able to finish a job in 60 days 'less than B'.
Let A's work is = x days.
Let B's work is = 3x days.
A able to do a work in 60 less than B.

Therefore,

A's work = B's work - 60.
So,
x=3x-60.
Then x=30.

A can complete the work in 30 days.
B can complete the work in 3*30 = 90 days.

A's one day work = 1/30 days.
B's one day work = 1/90 days.
A+B one day work = (1/30)+(1/90) = 4/90 days.
Therefore A and B can finish the work in = 90/4.
So the answer is : Option [B].

Kalyani said:   1 decade ago
What is the meaning of taking 3/2 in the problem. What's that ratio about?

Piyasa Dey said:   1 decade ago
If A does a work in 1 day.
therefor B does the same work in 3 days since A is thrice as good as workman as B.

Let A completes the work in x days, B will take (x + 60) days more than A takes.

Therefore 1:3 :: x :(x + 60).
Now according to the formula if a:b :: c:d.
Then it is considered as (a * d) = (b*c).

Applying this formula we get 1*(x + 60) = 3*x.
By solving we get x= 30 i.e A takes 30 days to complete the work.
Therefore B will take (30+60)=90 days.

A's one day work = 1/30 days.
B's one day work = 1/90 days.
A+B one day work = (1/30)+(1/90) = 4/90 days.
Therefore A and B can finish the work in = 90/4.


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