Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 21)
21.
A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:
Answer: Option
Explanation:
| Suppose A, B and C take x, | x | and | x | days respectively to finish the work. |
| 2 | 3 |
| Then, |  |
1 | + | 2 | + | 3 |  |
= | 1 |
| x | x | x | 2 |
 |
6 | = | 1 |
| x | 2 |
x = 12.
So, B takes (12/2) = 6 days to finish the work.
Discussion:
67 comments Page 7 of 7.
Keyan said:
1 decade ago
How to solve it in 1:2:3 basis?
Kumar said:
1 decade ago
How the work equation became as (1/x)+(2/x)+(3/x)=1/2
Ananth said:
1 decade ago
How the total work equation became as (1/x)+(2/x)+(3/x)=1/2
Please explain.
Please explain.
Srihari said:
1 decade ago
Hi Meera,
It is not right method because A+B+C's 1 day work is only 1/2 not 1/6.
It is not right method because A+B+C's 1 day work is only 1/2 not 1/6.
Meera said:
1 decade ago
A+B+C's 1 days work is = 1/6.
Therefore 2'days work (A+B+C) is=1/6*2=3.
B can do the work alone (2*3) =6.
So B takes 6 days to finish the work.
Is it right method? please anyone tell me.
Therefore 2'days work (A+B+C) is=1/6*2=3.
B can do the work alone (2*3) =6.
So B takes 6 days to finish the work.
Is it right method? please anyone tell me.
Ritanjali natua said:
1 decade ago
1/x+2/x+3/x=6/x
Afua said:
1 decade ago
Where's 6 coming from?
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