Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 21)
21.
A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:
4 days
6 days
8 days
12 days
Answer: Option
Explanation:

Suppose A, B and C take x, x and x days respectively to finish the work.
2 3

Then, 1 + 2 + 3 = 1
x x x 2

6 = 1
x 2

x = 12.

So, B takes (12/2) = 6 days to finish the work.

Discussion:
67 comments Page 1 of 7.

Afua said:   1 decade ago
Where's 6 coming from?

Ritanjali natua said:   1 decade ago
1/x+2/x+3/x=6/x

Meera said:   1 decade ago
A+B+C's 1 days work is = 1/6.

Therefore 2'days work (A+B+C) is=1/6*2=3.

B can do the work alone (2*3) =6.

So B takes 6 days to finish the work.

Is it right method? please anyone tell me.

Srihari said:   1 decade ago
Hi Meera,

It is not right method because A+B+C's 1 day work is only 1/2 not 1/6.

Ananth said:   1 decade ago
How the total work equation became as (1/x)+(2/x)+(3/x)=1/2

Please explain.

Kumar said:   1 decade ago
How the work equation became as (1/x)+(2/x)+(3/x)=1/2

Keyan said:   1 decade ago
How to solve it in 1:2:3 basis?

Shridhar said:   1 decade ago
As the ques. says,
time taken by A is twice that of B and thrice that of C,so
this means that

A=2*B=3*C ----(eq.1)
dividing the whole equation by lcm(1,2,3)=6,we get
A/6=B/3=C/2

Now
one third of the workdone of B is finished in 2 days
therefore complete workdone of B will be finished in 3*2=6 days.

Lordy said:   1 decade ago
once c the question pls it is mentioned a is twice of b OR thrice of c then how can we divide x,x/2,x/3. if it is mentioned as and then we can decide right?

Thameem said:   1 decade ago
here is another way of solving

given
a=2b
a=3c
a+b=1/2 (work from days)

use a's value in the equation

2b+b=1/2

then 3b=1/2
b=1/6

then b can done work alone in 6 days(days from work)


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