Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 19)
19.
A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in:
1 day
24
7 day
24
3 3 days
7
4 days
Answer: Option
Explanation:
Formula: If A can do a piece of work in n days, then A's 1 day's work = 1 .
n

(A + B + C)'s 1 day's work = 1 + 1 + 1 = 7 .
24 6 12 24

Formula: If A's 1 day's work = 1 , then A can finish the work in n days.
n

So, all the three together will complete the job in 24 days = 3 3 days.
7 7

Discussion:
24 comments Page 1 of 3.

Ramyasree said:   2 decades ago
How to write 24/7 as 3*3/7?

Baskar said:   2 decades ago
First you multiply 3 and denominator (3*7=21) and that coming answer add with numerator (21+3=24) then finally that answer divide by denominator (24/7=3*3/7)

Mansi said:   2 decades ago
Front value multiplied by dr. and added to nr value
for example 7*3=21 is added to nr value 21+3=24
hence 24/7

You can make the answere in nr/dr form and compare better thn converting in othr form

Praseetha said:   2 decades ago
How 1/n=n?

Simon said:   2 decades ago
I didn't get how you got 7/24.

Sanjukta Nayak said:   2 decades ago
Me confused,please help

Muthukumar said:   2 decades ago
I am not understand how to you got 7/24.

Maheswari said:   2 decades ago
i can't get... how 1/n

Mohit said:   2 decades ago
Hey look at the question first he is asking days for completion of work so If A's 1 day's work = 1/n then A can finish the work in n days its reciprocal of it.

Dharma said:   1 decade ago
A's work be x,
B's work be y
C's work be z

Total work done by A,B,C(A+B+C)=(X*Y*Z)/(XY+YZ+XZ)

Solution is:
x=12
y=6
z=24

A+B+C=(12*6*24)/(12*6+6*24+24*12)

= 24/7

= 3 and (3/7)


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