Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 19)
19.
A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in:
Answer: Option
Explanation:
| Formula: If A can do a piece of work in n days, then A's 1 day's work = | 1 | . |
| n |
| (A + B + C)'s 1 day's work = |  |
1 | + | 1 | + | 1 |  |
= | 7 | . |
| 24 | 6 | 12 | 24 |
| Formula: If A's 1 day's work = | 1 | , | then A can finish the work in n days. |
| n |
| So, all the three together will complete the job in | |
24 | days |
= | 3 | 3 | days. | 7 | 7 |
Discussion:
24 comments Page 3 of 3.
Deepshikha said:
8 years ago
Lcm of 24 12 6 is clearly 48 how are they getting 7/24?
Nitesh KC said:
8 years ago
In this question, it is found that all together can work in 1 /24 days can you guys suggest me how to find the fraction of work each of them do? Please explain.
Dhivyan K said:
3 years ago
Here, 24/7 (improper fraction) is converted into a mixed fraction (3 * 3/7).
(2)
ARTI said:
9 months ago
LCM OF 24,6,12 is 24 not 48 (2*2*3*2).
(1)
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