Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 19)
19.
A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in:
Answer: Option
Explanation:
| Formula: If A can do a piece of work in n days, then A's 1 day's work = | 1 | . |
| n |
| (A + B + C)'s 1 day's work = |  |
1 | + | 1 | + | 1 |  |
= | 7 | . |
| 24 | 6 | 12 | 24 |
| Formula: If A's 1 day's work = | 1 | , | then A can finish the work in n days. |
| n |
| So, all the three together will complete the job in | |
24 | days |
= | 3 | 3 | days. | 7 | 7 |
Discussion:
24 comments Page 1 of 3.
ARTI said:
9 months ago
LCM OF 24,6,12 is 24 not 48 (2*2*3*2).
(1)
Dhivyan K said:
3 years ago
Here, 24/7 (improper fraction) is converted into a mixed fraction (3 * 3/7).
(2)
Nitesh KC said:
8 years ago
In this question, it is found that all together can work in 1 /24 days can you guys suggest me how to find the fraction of work each of them do? Please explain.
Deepshikha said:
8 years ago
Lcm of 24 12 6 is clearly 48 how are they getting 7/24?
Saurabh said:
9 years ago
The given answer and explanations are seems to be a right solution.
Narayan said:
10 years ago
LCM of 24 6 12 is 48.
(1)
Sanjoy said:
1 decade ago
24A = 1, 6B = 1, 12C = 1.
A = 1/24, B = 1/6 C = 1/12.
Now let us consider x day is required if all are working together.
So (A+B+C)x = 1.
(1/24+1/6+1/12)x = 1.
((1+4+2)/24)x = 1.
7/24 x = 1.
x = 24/7.
x = 3 3/7.
A = 1/24, B = 1/6 C = 1/12.
Now let us consider x day is required if all are working together.
So (A+B+C)x = 1.
(1/24+1/6+1/12)x = 1.
((1+4+2)/24)x = 1.
7/24 x = 1.
x = 24/7.
x = 3 3/7.
(3)
Tamanna said:
1 decade ago
Its very easy:-
A's 1 day's work = 1/24.
B's 1 day's work = 1/6.
C's 1 day's work = 1/12.
Thus, {A+B+C}'s 1 day's work = 1/24+1/6+1/12.
= 1+4+2/24[taking LCM=24].
= 7/24.
Thus, working together they will complete work in 24/7 days or 3 3/7 days.
A's 1 day's work = 1/24.
B's 1 day's work = 1/6.
C's 1 day's work = 1/12.
Thus, {A+B+C}'s 1 day's work = 1/24+1/6+1/12.
= 1+4+2/24[taking LCM=24].
= 7/24.
Thus, working together they will complete work in 24/7 days or 3 3/7 days.
(1)
Vivek said:
1 decade ago
Hi there is a different way as well.
A 24
B 6
C 12
Now take the number that multiplies with all i.e 24.
So A 1
B 4
C 2 add all of them = 7.
Now divide 24 by 7 you will get answer = 3 3/7.
A 24
B 6
C 12
Now take the number that multiplies with all i.e 24.
So A 1
B 4
C 2 add all of them = 7.
Now divide 24 by 7 you will get answer = 3 3/7.
DopeBoy said:
1 decade ago
If the work done by A is n , then the work done is one day is 1/n.
Similar to (1 part of the work)/complete work.
Total work done together in one day is : 1/n = 1/12+1/24+1/6= 7/24
Total work done together : n = 24/7.
Similar to (1 part of the work)/complete work.
Total work done together in one day is : 1/n = 1/12+1/24+1/6= 7/24
Total work done together : n = 24/7.
(1)
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