Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 19)
19.
A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in:
Answer: Option
Explanation:
| Formula: If A can do a piece of work in n days, then A's 1 day's work = | 1 | . |
| n |
| (A + B + C)'s 1 day's work = |  |
1 | + | 1 | + | 1 |  |
= | 7 | . |
| 24 | 6 | 12 | 24 |
| Formula: If A's 1 day's work = | 1 | , | then A can finish the work in n days. |
| n |
| So, all the three together will complete the job in | |
24 | days |
= | 3 | 3 | days. | 7 | 7 |
Discussion:
24 comments Page 3 of 3.
Praseetha said:
2 decades ago
How 1/n=n?
Mansi said:
2 decades ago
Front value multiplied by dr. and added to nr value
for example 7*3=21 is added to nr value 21+3=24
hence 24/7
You can make the answere in nr/dr form and compare better thn converting in othr form
for example 7*3=21 is added to nr value 21+3=24
hence 24/7
You can make the answere in nr/dr form and compare better thn converting in othr form
Baskar said:
2 decades ago
First you multiply 3 and denominator (3*7=21) and that coming answer add with numerator (21+3=24) then finally that answer divide by denominator (24/7=3*3/7)
Ramyasree said:
2 decades ago
How to write 24/7 as 3*3/7?
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