Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Answer: Option
Explanation:
Let the duration of the flight be x hours.
| Then, | 600 | - | 600 | = 200 |
| x | x + (1/2) |
 |
600 | - | 1200 | = 200 |
| x | 2x + 1 |
x(2x + 1) = 3
2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
Discussion:
206 comments Page 16 of 21.
Mangesh said:
1 decade ago
Please tell me in separate steps to solve this example.
Priya said:
1 decade ago
Yes, please tell me if any short method is available.
(1)
Akash said:
10 years ago
How will 2x+1 will come it it 600/(x+1/2) = 1200/x+1?
Suresh said:
10 years ago
Please tell me the formula of these type of problems.
Madhav said:
8 years ago
Can anyone explain 1st step, I'm not understanding.
Ramesh said:
1 decade ago
Why the difference in speed matched with 200km/hr?
Madhav said:
8 years ago
How 600/x-600/x+2=200?
Please explain this step.
Please explain this step.
Sundarraj said:
2 decades ago
Thanks Kiran. Your answer is very easy to grasp.
Chris said:
1 decade ago
Please can anyone tell me what is the LCM taken?
Hemant said:
1 decade ago
(2x+1)(600)-1200x=200(2x^2 +x)
2x^2 +x=3
explain
2x^2 +x=3
explain
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