Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
1 hour
2 hours
3 hours
4 hours
Answer: Option
Explanation:

Let the duration of the flight be x hours.

Then, 600 - 600 = 200
x x + (1/2)

600 - 1200 = 200
x 2x + 1

x(2x + 1) = 3

2x2 + x - 3 = 0

(2x + 3)(x - 1) = 0

x = 1 hr.      [neglecting the -ve value of x]

Discussion:
205 comments Page 1 of 21.

Zary said:   2 decades ago
Hi frnds! I'm not getting why you are taking.

600 - 600 = 200.

X x + (1/2) ?

Please explain in detail!

Nirmal.s said:   2 decades ago
Am also having de same doubt yaar.

Lathesh said:   2 decades ago
Need more detailed explanation.

Kiran.p said:   2 decades ago
We know that speed=distance/time;

Let us assume time as x,then actual speed=600/x;

Now the time is incremented to 30 min right,

So, now the speed=600/(x+1/2)

Here we take the time in hrs so (x+1/2).

In the problem the speed is reduced by 200km/hr

So the diff btwn speed is equal to 200km/hr.

i.e. 600/x-600/x+(1/2)=200
(2)

Sundarraj said:   2 decades ago
Thanks Kiran. Your answer is very easy to grasp.

Sundar raj said:   2 decades ago
@Kiran

your answer is right only. But can you briefly explain how to find the value X from 2x2 + x - 3 = 0.

Bhavana said:   2 decades ago
2x2 + x - 3 = 0.

2x2 - 2x + 3x - 3 = 0.

2x(x - 1) + 3(x- 1) = 0.

(2x + 3) (x - 1) = 0.

X=3/2 or x=1.

Hope you got d answer Sundar.

Sivaram said:   1 decade ago
Hi Bhavana, I can't get the answer why you got 1/2. How you get it?

Neelima said:   1 decade ago
60 mins = 1 hr

Then, 30 mins = 1/2 hr.

Sivakumaran said:   1 decade ago
X (2x + 1) = 3.

How this step comes along.


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