Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
1 hour
2 hours
3 hours
4 hours
Answer: Option
Explanation:

Let the duration of the flight be x hours.

Then, 600 - 600 = 200
x x + (1/2)

600 - 1200 = 200
x 2x + 1

x(2x + 1) = 3

2x2 + x - 3 = 0

(2x + 3)(x - 1) = 0

x = 1 hr.      [neglecting the -ve value of x]

Discussion:
211 comments Page 22 of 22.

Sagarika M said:   1 month ago
Flight travells 600kmph.

The speed reduced by 200kmph means 600-200=400kmph, so it was travelling at 400kmph.
Now, time taken to travel 400kmph is t+30min = t + 0.5hr.
=>s=d/t,
=>400kmph = 600km/t + 0.5hr.
=>400km/1hr = 600km/t + 0.5hr.
=>400km(t+0.5hr)= 600km(1hr).
=>2t + 1hr = 3hr.
=>2t = 3hr - 1hr.
=>t=1hr


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