Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Answer: Option
Explanation:
Let the duration of the flight be x hours.
| Then, | 600 | - | 600 | = 200 |
| x | x + (1/2) |
 |
600 | - | 1200 | = 200 |
| x | 2x + 1 |
x(2x + 1) = 3
2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
Discussion:
205 comments Page 2 of 21.
Shanthi said:
1 decade ago
Its simple only...take LCM of (600/x)-(1200/(2x+1))=200
you get (2x+1)(600)-1200x=200(2x^2 +x)
2x^2 +x=3
which is nothing but x(2x+1)=3
you get (2x+1)(600)-1200x=200(2x^2 +x)
2x^2 +x=3
which is nothing but x(2x+1)=3
Jaanaki said:
1 decade ago
Thank you shanthi.
Rafi said:
1 decade ago
Your right shanti but is there any easy and time saving solution for it?
Priya said:
1 decade ago
Yes, please tell me if any short method is available.
(1)
Vishnu said:
1 decade ago
Thank you kiran.
Deepak said:
1 decade ago
1)600/x-1200/2x+1= 200
2)x(2x + 1) = 3 pls explain these steps
2)x(2x + 1) = 3 pls explain these steps
Appu said:
1 decade ago
Can anybody solve (600/x)-600(x+1/2)=200?
Karthik said:
1 decade ago
(600/x)-600/(x+1/2)=200
(600/x)-600*2/(2x+1)=200
take LCM we will get
(600(2x+1)-600*2*x)/x*(2x+1)=200
600(2x+1)-600*2*x=200*x*(2x+1)
600(2x+1)-200*x*(2x+1)=600*2*x
i think now it ll b easy to simply
(600/x)-600*2/(2x+1)=200
take LCM we will get
(600(2x+1)-600*2*x)/x*(2x+1)=200
600(2x+1)-600*2*x=200*x*(2x+1)
600(2x+1)-200*x*(2x+1)=600*2*x
i think now it ll b easy to simply
Chris said:
1 decade ago
Please can anyone tell me what is the LCM taken?
Hemant said:
1 decade ago
(2x+1)(600)-1200x=200(2x^2 +x)
2x^2 +x=3
explain
2x^2 +x=3
explain
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