Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Answer: Option
Explanation:
Let the duration of the flight be x hours.
| Then, | 600 | - | 600 | = 200 |
| x | x + (1/2) |
 |
600 | - | 1200 | = 200 |
| x | 2x + 1 |
x(2x + 1) = 3
2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
Discussion:
206 comments Page 17 of 21.
Priya said:
8 years ago
2x^2 - 2x + 3x - 3 = 0. How we get it? Explain.
Ajit said:
8 years ago
Thanks for your valuable explanation @Bhavana.
Aju said:
7 years ago
To find the speed;
600/X-200 - 600/X = 0.5.
600/X-200 - 600/X = 0.5.
Esha said:
6 years ago
How do we get x(2x + 1) = 3? please explain.
(1)
Sivakumaran said:
1 decade ago
X (2x + 1) = 3.
How this step comes along.
How this step comes along.
Hemant said:
1 decade ago
x-2x+2x+x/x+x+1, please solve this problem.
Hemant said:
1 decade ago
x-2x+2x+x/x+x+1, please solve this problem.
Priyanka said:
5 years ago
Can anyone explain in a simple way? please.
(1)
Appu said:
1 decade ago
Can anybody solve (600/x)-600(x+1/2)=200?
Nirmal said:
9 years ago
How you got 1200/2x+1? Please explain it.
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