Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Answer: Option
Explanation:
Let the duration of the flight be x hours.
| Then, | 600 | - | 600 | = 200 |
| x | x + (1/2) |
 |
600 | - | 1200 | = 200 |
| x | 2x + 1 |
x(2x + 1) = 3
2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
Discussion:
206 comments Page 15 of 21.
Sivaram said:
1 decade ago
Hi Bhavana, I can't get the answer why you got 1/2. How you get it?
Diya said:
10 years ago
How can we add. Minutes to the hours like 200 hours and 30 minutes.
Deepak said:
1 decade ago
1)600/x-1200/2x+1= 200
2)x(2x + 1) = 3 pls explain these steps
2)x(2x + 1) = 3 pls explain these steps
Dinesh said:
1 decade ago
2x^2+x-3=0 how to solve this factorisation? So please help me.
Navin said:
4 years ago
@Saravanakgopi.
Thanks for simplifying the answer in detail.
Thanks for simplifying the answer in detail.
@ngel said:
1 decade ago
= x-(x+1/2) it simplify as,
= x-2x+1 = 0.
= -x+1 = 0.
x = 1.
= x-2x+1 = 0.
= -x+1 = 0.
x = 1.
Hunny said:
1 decade ago
600/(x-200) - 600/x = 30/60(in hrs)
Please anyone explain.
Please anyone explain.
Dean said:
1 decade ago
1/2 up --> 1/3 down. Therefore, 200 = 1/3 and 1 = 600.
Sunita said:
1 decade ago
Hey Saravanakgopi. How did you get 5400? please explain.
Anu said:
1 decade ago
@Saravanakgopi tell me how you get 5400 in your result.
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