Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
1 hour
2 hours
3 hours
4 hours
Answer: Option
Explanation:

Let the duration of the flight be x hours.

Then, 600 - 600 = 200
x x + (1/2)

600 - 1200 = 200
x 2x + 1

x(2x + 1) = 3

2x2 + x - 3 = 0

(2x + 3)(x - 1) = 0

x = 1 hr.      [neglecting the -ve value of x]

Discussion:
206 comments Page 14 of 21.

Naziya said:   10 years ago
Any one solve this simple and shortly? How this x+1/2 came? I'm not getting.

Vineet said:   8 years ago
Hi, Can anyone tel that how to calculate speed and what is the final answer?

Manik jaat said:   1 decade ago
Saravanakgopi can you please tell me that how you get 5400 instead of 600 ?
(1)

Aarman said:   1 decade ago
Please solve anyone this equation 600/x-600/x+1/2=200 I can't understand.

Rafi said:   1 decade ago
Your right shanti but is there any easy and time saving solution for it?

Aditya said:   8 years ago
Does anybody think the 1/2 should be added to make the answer to 1.5hr?

Gobinath P said:   7 years ago
Any other ways to solve this question? Please tell me the shortcut way.

Muzzu said:   6 years ago
T+30 = 600/400,
T+30/60 = 3/2,
T+1/2 = 3/2,
T= 3/2-1/2,
T= 1 hour.
(3)

Khushbu said:   1 decade ago
@Avy.

In equation (2x-3)(x+1) =0.
Then x=3/2 and x = -1.
So how x=1?

Kavita said:   1 decade ago
How you take 1200/2x +1? If you get 1200 then how its possible 2x+1.


Post your comments here:

Your comments will be displayed after verification.