Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = |  |
9 | x 60 |  min |
= 10 min. |
| 54 |
Discussion:
205 comments Page 9 of 21.
Swathi said:
9 years ago
Simple formula:
Stoppage time = (se - si) / se.
Where se = excluding stoppage.
si = including stoppages.
st = (54 - 45) / 54.
= 9/54.
= 1/6 hr.
= 1/6 * 60min.
= 10min.
Stoppage time = (se - si) / se.
Where se = excluding stoppage.
si = including stoppages.
st = (54 - 45) / 54.
= 9/54.
= 1/6 hr.
= 1/6 * 60min.
= 10min.
Yash soni said:
8 years ago
I'm not clear why we take 54. I think we take 45 because in 54 the bus is not stopped then how can 54 gives us the stoppage time?
If we take 45 so we get the answer (12).
If we take 45 so we get the answer (12).
Umakanta langpoklakpam said:
8 years ago
Due to stoppages, the bus lags =(54-45)Kmph=9Kmph in speed.
So, time taken at each stoppages= Speed /original speed.
=9/54 hrs,
=9*60/54mins,
=540/54mins,
=10mins.
So, time taken at each stoppages= Speed /original speed.
=9/54 hrs,
=9*60/54mins,
=540/54mins,
=10mins.
Karthik said:
4 years ago
The bus travelled only 45kms. Hence, it would be correct to divide 45 (and not 50) and multiply 60 with 9 kms (less travelled).
Am I right? please clarify for me.
Am I right? please clarify for me.
Brijesh Kesharia said:
1 decade ago
A car starts running with the initial speed of 40 km/h with its speed increasing every hour by 5 km/h. How many hours will it take to cover a distance of 385 km?
HASHI said:
2 years ago
Its very simple,
Firstly,
54 - 45 =9 due to stoppages,it covers 9km less.
Time taken to cover 9km = (9/54 x 60) =10mins. And in "1 min there are 60 seconds".
Firstly,
54 - 45 =9 due to stoppages,it covers 9km less.
Time taken to cover 9km = (9/54 x 60) =10mins. And in "1 min there are 60 seconds".
(11)
Suyash More said:
9 years ago
Here distance is constant.
Let x be the time for which the vehicle speed.
Hence, 54 * (60 - x) = 45 * (60).......(s1 * t1= s2 * t2).
x = 10 min is the answer.
Let x be the time for which the vehicle speed.
Hence, 54 * (60 - x) = 45 * (60).......(s1 * t1= s2 * t2).
x = 10 min is the answer.
Chahat Mishra said:
6 months ago
@All.
Very easy approach:
S1 = 54.
S2 = 45.
By ratio method:
The speed diff is 9kmph.
distance = 9 km.
T= d/s.
t = 9/54 = 1/6 hr=(1/6) * 60min.
t = 10 min.
Very easy approach:
S1 = 54.
S2 = 45.
By ratio method:
The speed diff is 9kmph.
distance = 9 km.
T= d/s.
t = 9/54 = 1/6 hr=(1/6) * 60min.
t = 10 min.
(31)
Shravani N said:
8 months ago
Why have we taken the speed of the train without stoppages (that is 54kmph) for calculating the time taken by the bus to cover 9 km?
Anyone, please clarify.
Anyone, please clarify.
(16)
Aditya said:
10 years ago
There is a formula for this questions:
(V1-v2)/v1.
V1= Without stoppage velocity.
V2 = With stoppage.
Result is in hour. Multiply by 60 to get minutes.
(V1-v2)/v1.
V1= Without stoppage velocity.
V2 = With stoppage.
Result is in hour. Multiply by 60 to get minutes.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers