Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = | ![]() |
9 | x 60 | ![]() |
= 10 min. |
54 |
Discussion:
205 comments Page 8 of 21.
Farhat said:
9 years ago
See it is covering 54km - 45km = 9km extra distance right. But that extra distance it is covering with the speed of 54kmph. So, time taken t = distance/speed = 9km/54kmph.
= (9/54) hr = (9 * 60/54) min = 10 min.
= (9/54) hr = (9 * 60/54) min = 10 min.
Rahul said:
1 decade ago
How did u get as 9 km, as they have subtracted the two speeds...!!!! if they have subtracted them it would result as 9 km/hr!!!! Then hw s it possible to get the time...???? May be the question is wrong..!!!!
Kunal said:
1 decade ago
If the bus doesn't stop for an hour it travels 54 km at a constant speed of 54kph. But it stops for some time 't' and covers 45 km in the remaining (60-t) mins at 54kph.
45 = (60-t) * (54/60) => t=10mins.
45 = (60-t) * (54/60) => t=10mins.
Shro said:
1 decade ago
Hey somebody explain it clearly 54km/hr-45km/hr=9km/hr
Why to consider only 9km?
why not 9km/hr?
The answer is clearly 9km /hr.
Then why to convert it into minutes?
it should be only 9/54= 1/6 or say 0.16
Why to consider only 9km?
why not 9km/hr?
The answer is clearly 9km /hr.
Then why to convert it into minutes?
it should be only 9/54= 1/6 or say 0.16
RAJU said:
7 years ago
Bus can cover distance without stops for 60mins(60 * 54) = 3240m.
Bus can cover distance with stops for 60mins (60 * 45) = 2700m.
difference distance = 540m.
Time = distance/speed = 540/54 = 10mins.
Bus can cover distance with stops for 60mins (60 * 45) = 2700m.
difference distance = 540m.
Time = distance/speed = 540/54 = 10mins.
Aranv gupta said:
2 years ago
If he travels for 10 km.
54 kmph means 54x10= 540.
45 kmph means 45x10= 450.
Difference of distance 540-450=90km,
Difference of speed 54-45=9.
.Distance=speed x time.
90 = 9xtime,
time = 10.
54 kmph means 54x10= 540.
45 kmph means 45x10= 450.
Difference of distance 540-450=90km,
Difference of speed 54-45=9.
.Distance=speed x time.
90 = 9xtime,
time = 10.
(42)
Mir Rokon Uddin said:
9 years ago
His regular speed reduce 54k/h to 45k/h.
So we have to find out the missing time from the regular speed.
The difference of the distance is 9kmh.
So missing time = (1* 9/54) * 60min.
= 10min.
So we have to find out the missing time from the regular speed.
The difference of the distance is 9kmh.
So missing time = (1* 9/54) * 60min.
= 10min.
Kathleena said:
9 years ago
Car travels with an average speed of 70 km/hr from Magallanes interchange to bicutan in 5 mi how far are these two places? How fast is the car travelling after 2 mi?
Please sole this.
Please sole this.
Kavya said:
1 decade ago
As we have subtracted the two speeds, then it would result as 9 kmph!
If 54 kmph means for 1hr------> 54km.
So now 9 kmph means 1hr------> 9km right so the answer is 60min.
If 54 kmph means for 1hr------> 54km.
So now 9 kmph means 1hr------> 9km right so the answer is 60min.
Akriti said:
1 decade ago
Here speed is given - 54 (excluding stoppages), 45(including ).
Time taken at stoppages -d/t.
So 9 kmph, distance - 9*60.
540/54 because (distance /time), we got 10min.
Time taken at stoppages -d/t.
So 9 kmph, distance - 9*60.
540/54 because (distance /time), we got 10min.
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