Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = |  |
9 | x 60 |  min |
= 10 min. |
| 54 |
Discussion:
205 comments Page 7 of 21.
Vipin ydv said:
1 year ago
Solution:
S1 ---> 54 kmph,
S2 ---> 45 kmph
S1 means in 60 min bus travel 54 km.
S2 means 60-t(required time).
S2(45) -----> (60-t)min.
1 min -----> s2/60 - t.
60 min -----> s2 * 60/60 - t = s1.
t = 45 * 60/54,
t = 10 min.
S1 ---> 54 kmph,
S2 ---> 45 kmph
S1 means in 60 min bus travel 54 km.
S2 means 60-t(required time).
S2(45) -----> (60-t)min.
1 min -----> s2/60 - t.
60 min -----> s2 * 60/60 - t = s1.
t = 45 * 60/54,
t = 10 min.
(3)
Karthik said:
7 years ago
Simply, the solution is;
60min --> 54km
x min --> 45
>>x=50;
This means with stoppages it is taking 50 min to reach 45km.
but now without stoppage it is taking 60 min so with stoppage it is taking extra 10 min.
60min --> 54km
x min --> 45
>>x=50;
This means with stoppages it is taking 50 min to reach 45km.
but now without stoppage it is taking 60 min so with stoppage it is taking extra 10 min.
MMMMM said:
9 years ago
The speed of a train is 80 kmph and for every bogie added, the speed decreases by 10%. How many minimum numbers of bogies should be added to reduce the speed of the train to less than 50 km/h?
Can anyone tell me the answer?
Can anyone tell me the answer?
Saurabh said:
1 decade ago
For those who got i2 min as answer.
Solve like this;
As distance is same....
54=d/(1-x).........(1) where x is the stoppage time.
45=d/1.............(2).
Solving eq 1 & 2,we get x=0.166 hrs. So in minutes ANS = 10.
Solve like this;
As distance is same....
54=d/(1-x).........(1) where x is the stoppage time.
45=d/1.............(2).
Solving eq 1 & 2,we get x=0.166 hrs. So in minutes ANS = 10.
Surya said:
7 years ago
To cover 54km it takes 60 min, for 1 km time taken = 60/54, then for 45km time =(60/54)*45 = 50min, to cover 45km it just need 50min but it take 60min with stoppage, it take extra 10 min which means the bus stop for 10min.
Yash said:
1 decade ago
I tried by this method:
- - - Speed Time Distance.
Stop : 54 1h D.
Non-S: 45 1-X h D.
D is common for both, so,
54 * 1h = 45*(1-x)h.
X = 1/5 hr ==> 12 mins.
What went wrong in this method.
- - - Speed Time Distance.
Stop : 54 1h D.
Non-S: 45 1-X h D.
D is common for both, so,
54 * 1h = 45*(1-x)h.
X = 1/5 hr ==> 12 mins.
What went wrong in this method.
Ramesh Nayak said:
8 years ago
The distance between A and B is 999km.The express train travels place A at 6 a.m. and runs at the speed of 55.5 kmph. The train stops on the way for 1 hour 20 minute.The train reaches B at?
Please solve this question.
Please solve this question.
Shriii said:
8 years ago
@Yash Soni.
If we take 45 then the bus is already stopped. And 45 is not the actual bus speed. It's the speed that is just calculated when the bus is stopped at stops. So 54 is its actual speed. So we should take 54.
If we take 45 then the bus is already stopped. And 45 is not the actual bus speed. It's the speed that is just calculated when the bus is stopped at stops. So 54 is its actual speed. So we should take 54.
Basil said:
6 years ago
Can't we consider like taking the ratio of speed and time since distant is constant, time is inversely proportional to speed?
From which we can get the ratio of stoppage to total travel time. Please explain to me.
From which we can get the ratio of stoppage to total travel time. Please explain to me.
Jaya said:
1 decade ago
The easy method: For 1 hour the bus travels for 54 km then for one min its 54/60=0.9km.
So if the bus stops for one minute it travel 0.9 km less so if the bus travels 9 km less then it might stopped for 10 min.
So if the bus stops for one minute it travel 0.9 km less so if the bus travels 9 km less then it might stopped for 10 min.
(4)
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